Can someone help me please
1 answer:
Answer:
a. 1200 f. 900
b. 600 g. 5700
c. 900 h. 4800
d. 300 i. 8300
e. 800 j. 8500
Step-by-step explanation:
First of all, you need to compute the sums. I find a calculator handy for this.
To round to hundreds, you can examine the digit in the next place to the right of the hundreds place. That digit in the tens place needs to be compared to 5. If it is 5 or greater, add 1 to the digit in the hundreds place. After you have done that, set the digits to the right of the hundreds place to zero.
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Alternatively, you can add 1/2 of 100 to the sum, then set the digits to the right of the 100s place to zero. (Adding 50 will only change the 100's place digit if the 10's place digit is 5 or more.) This method doesn't require you do any thinking about the size of the digit; it is purely mechanical.
The sums and their rounded values are ...
a. 1221 ⇒ 1200
b. 568 ⇒ 600
c. 931 ⇒ 900
d. 347 ⇒ 300
e. 798 ⇒ 800
f. 911 ⇒ 900
g. 5681 ⇒ 5700
h. 4766 ⇒ 4800
i. 8328 ⇒ 8300
j. 8507 ⇒ 8500
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Answer:
Using the normal probability distribution, with a capacity of 350, it is enough for all abused on 90.82% of nights.
274 shelters will be needed.
Step-by-step explanation:
Problems of normally distributed samples are solved using the z-score formula.
In a set with mean and standard deviation
, the zscore of a measure X is given by:
The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.
In this problem, we have that:
If the city’s shelters have a capacity of 350, will that be enough places for abused women on 95% of all nights?
What is the percentile of 350?
This is the pvalue of Z when X = 350.
has a pvalue of 0.9082.
Using the normal probability distribution, with a capacity of 350, it is enough for all abused on 90.82% of nights.
If not, what number of shelter openings will be needed?
The 95th percentile, which is X when Z = 1.645. So
274 shelters will be needed.