It's false. The bulb does not shine if the circuit is not closed. The bulb does not shine if the bulb is broken.
Line up oz and % and cross multiply
If 90oz. Is 100%
23oz is ? %
?=(23•100)/90= 25.55555~25.56% (D)
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C = 9.5t.....when t = 14
c = 9.5(14)
c = $ 133 <==

Let's factor all four of these before we multiply.
x² - 25 We want two numbers that add to -25 and multiply to 0.
= (x+5)(x-5)
x² - 2x
Both terms are divisible by x.
= x(x-2)
x - 2unfactorable
x² + 5x
Both terms are divisible by x.
= x(x+5)
Now we have this:

Let's go ahead and multiply across.

Cancel out the (x+5) and (x-2) from the top and the bottom.