<u>The present age of the man is 36 years and his son is 11 years.</u>
Answer:
Solution given:
let the age of man be x.
and his son be y.
By question
x-6=6(y-6)
x=6y-36+6
x=6y-30. ......(1)
and
3(x+4)=8(y+4)
3x+12=8y+32
3x=8y+32-12
3x=8y+20. ...(2)
substituting value of x in equation 2 ,we get
3(6y-30)=8y+20
18y-90=8y+20
18y-8y=90+20
10y=110
y=110/10
y=11 years
again substituting value of y in equation 1 we get
x=6*11-30
x=66-30
x=36 years
Answer:
75
Step-by-step explanation:
f(1) = 7
f(n) = 3f(n-1) + 3
So what you are trying to do here is find the recursive value (that's what it is called) for f(n). Computers love this sort of thing, but we humans have to do it slowly and carefully.
So let's try f(2)
That means that f(2) = 3*f(n-1) + 3
but if f(2) is used it means that you have to know f(2-1) which is just f(1) and we know that.
so f(2) = 3*f(1)+3
f(2) = 3*7 + 3
f(2) = 21 + 3
f(2) = 24
Now do it again. We now know F(2), so we should be able to find f(3)
f(3) = 3*f(3 - 1) + 3
f(3) = 3*f(2) + 3 We know that f(2) = 24
f(3) = 3* 24 + 3
f(3) = 72 + 3
f(3) = 75
Answer:
(i) The length of AC is 32 units, (ii) The length of BC is 51 units.
Step-by-step explanation:
(i) Let suppose that AB and BC are collinear to each other, that is, that both segments are contained in the same line. Algebraically, it can be translated into this identity:
If we know that 
and 
, then:
The length of AC is 32 units.
(ii) Let suppose that AB and AC are collinear to each other, that is, that both segments are contained in the same line. Algebraically, it can be translated into this identity:
If we know that 
and 
, then:
The length of BC is 51 units.
<span> Just plug in the value of b=3 in 4b^4, then you solve it, and your answer is 324</span>
Answer:
$72500
Step-by-step explanation:
$72500
