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Hoochie [10]
3 years ago
5

7 inches by 4 inches. the frame is created from 10 square inches of framing material

Mathematics
1 answer:
coldgirl [10]3 years ago
5 0
74 inches whskdnsaskfis
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For the level 3 course, exam hours cost twice as much as workshop hours, workshop hours cost twice as much as lecture hours. How
natulia [17]
<h2>Answer</h2>

Cost of lectures = $7.33 per hour

<h2>Explanation</h2>

Let e the cost of the exam hours

Let w be the cost of the workshop hours

Let l be the cost of the lecture hours.

We know from our problem that exam hours cost twice as much as workshop, so:

e=2w equation (1)

We also know that workshop hours cost twice as much as lecture hours, so:

w=2l equation (2)

Finally, we also know that 3hr exams 24hr workshops  and 12hr lectures cost $528, so:

3e+24w+12l=528 equation (1)

Now, lets find the value of l:

Step 1.  Solve for l in equation (3)

3e+24w+12l=528

12l=528-3e-24w equation (4)

Step 2. Replace equation (1) in equation (4) and simplify

12l=528-3e-24w

12l=528-3(2w)-24w

12l=528-6w-24w

12l=528-30w equation (5)

Step 3. Replace equation (2) in equation (5) and solve for l

12l=528-30w

12l=528-30(2l)

12l=528-60l

72l=528

l=\frac{528}{72}

l=\frac{22}{3}

l=7.33

Cost of lectures  = $7.33 per hour



3 0
3 years ago
Read 2 more answers
How many natural numbers from 78 to 24?
I am Lyosha [343]
54 numbers is the answer
3 0
3 years ago
What times 1/10 equals 0.49
Fudgin [204]
1/10x = 0.49
x = (0.49) / (1/10)
x = 0.49 * 10/1
x = 4.9 <==
6 0
3 years ago
melanie spent 4 hours babysitting, charges $16 and then charge per hour. the total she earns can be represented like this $4x+$1
timurjin [86]
$6.50 per hour of babysitting
3 0
3 years ago
B. A play contains 18 speaking roles, where 10 are male and 8 are female. If the director can choose from among 15 male actors t
shepuryov [24]

Answer:

3168

Step-by-step explanation:

Here, we have s combination problem as we are selecting. The question is quite straightforward.

What the director needs to do is simply select 10 males from the total 15 males and also select 8 females from the total 11 females and add the results.

To select 10 from 15, we simply compute as 15C10 which equals 3003 ways

To select 8 from 11, we simply compute 11C8 which equals 165 ways

We simply add both to get the numbers of possible casts which is 3003 + 165 = 3168 possibilities

4 0
3 years ago
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