Based off the measures of the arcs DC and AB, your answer should be B. 36 Hope it helps.
Answer:
one unit vector is ur=(-1/√3 ,1/√3 ,1/√3 )
Step-by-step explanation:
first we need to find a vector that is ortogonal to u and v . This vector r can be generated through the vectorial product of u and v , u X v :![r=u X v =\left[\begin{array}{ccc}i&j&k\\1&0&1\\0&1&1\end{array}\right] = \left[\begin{array}{ccc}0&1\\1&1\end{array}\right]*i + \left[\begin{array}{ccc}1&0\\1&1\end{array}\right]*j + \left[\begin{array}{ccc}1&0\\0&1\end{array}\right]*k = -1 * i + 1*j + 1*k = (-1,1,1)](https://tex.z-dn.net/?f=r%3Du%20X%20v%20%3D%5Cleft%5B%5Cbegin%7Barray%7D%7Bccc%7Di%26j%26k%5C%5C1%260%261%5C%5C0%261%261%5Cend%7Barray%7D%5Cright%5D%20%3D%20%5Cleft%5B%5Cbegin%7Barray%7D%7Bccc%7D0%261%5C%5C1%261%5Cend%7Barray%7D%5Cright%5D%2Ai%20%2B%20%20%5Cleft%5B%5Cbegin%7Barray%7D%7Bccc%7D1%260%5C%5C1%261%5Cend%7Barray%7D%5Cright%5D%2Aj%20%2B%20%5Cleft%5B%5Cbegin%7Barray%7D%7Bccc%7D1%260%5C%5C0%261%5Cend%7Barray%7D%5Cright%5D%2Ak%20%3D%20-1%20%2A%20i%20%2B%201%2Aj%20%2B%201%2Ak%20%3D%20%28-1%2C1%2C1%29)
then the unit vector ur can be found through r and its modulus |r| :
ur=r/|r| = 1/[√[(-1)²+(1)²+(1)²]] * (-1,1,1)/√3 =(-1/√3 ,1/√3 ,1/√3 )
ur=(-1/√3 ,1/√3 ,1/√3 )
Answer:
The range is 4
Step-by-step explanation:
<u>To find the range, you subtract the lowest number from the highest number.</u>
<u />
<u>Example: If the set was: 1, 2, 6, 6, 8, 10</u>
What is the highest number: 10
What is the lowest number: 1
<em>You will do this -> 10 - 1 = 9</em>
<em />
<u>Problem: 8, 9, 9, 8, 8, 5, 8</u>
What is the highest number: 9
What is the lowest number: 5
<em>9 - 5 = 4</em>
<em />
Answer: The range is 4
Answer:
H(t) = 15 -6sin(2.5π(t -0.5))
Step-by-step explanation:
For midline M, amplitude A, period T and time t0 at which the function is decreasing from the midline, the function can be written as ...
H(t) = M -Asin(2π/T(t -t0))
Using the given values of M=15, A=6, T=0.8 and t0 = 0.5, the equation is ...
H(t) = 15 -6sin(2.5π(t -0.5))
Answer:
Step-by-step explanation:
A company manufactures two types of fishing rods, standard and folding. The cost of manufacturing 2 folding rods and 1 standard is $35. If 5 standard and 7 folding rods were manufactured, the cost would be $145. How much does it cost to manufacture each type of rod.
let S = standar rod
F= folding rod
2F + S =35
2F + S -2F =35 - 2F
or S = 35-2F
7F + 5S =145
7F + 5S -7F =145 -7F
or 5S =145-7F
Since S=35-2F
5S = 5X (35-2F)
5S = 175 -10F
which equals 145-7F
175-10F = 145-7F
175-10F +10F = 145 -7F + 10F
175 = 145 +3F
175 -145 =145 -145 + 3F
30 = 3F
F = 10
but S =35 - 2F
so S = 35 -2X10
S = 35-20 =15
check:
if F = 10 and S = 15
then 5S +7F should equal 145
5X15 + 7X10 = 75 + 10 =145
so F=10, S=15
