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3 years ago

10

If the spinner is spun twice, what is the probability that the numbers that are spun don't match?

1 answer:

Strike441 [17]3 years ago

8 0

Four possible way depending on what you spin if it is dominoes it would be twelve

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What is the value of x?

monitta

The ans is choice D. since there nothing under 5x, imagine there is a 1 under. After that, you can simply cross multiply, so it would be 1(6+8x)= 2(5x). 6+8x= 10x now combine like terms so subtract 8x from both sides and divide 6 by 2 and you will get 3

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What is the greatest common factor and least common multiple of 45 75 and 90?

Ghella [55]

15 and 450 because you divide and multiply until you get the same number

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3 years ago

I am half way between two consecutive numbers. The product of the two numbers is 650. what number am I ?

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3 years ago

If nelson invests $5000 for 4 years and earns $600, what is the simple interest rate?

klio [65]

Answer: Simple interest rate = 3%.

Step-by-step explanation: We are given invested amount = $5000.

Number of years of investment = 4 years.

Interest earned = $600.

Simple interest formula.

I = P R T.

Where I is the earned interest, P is the invested amount , R is the rate of interest and T is the time in years.

Plugging values in formula, we get

600 = 5000 × R × 4

600 = 20000R.

Dividing both sides by 20000, we get

$\frac{600}{20000} = \frac{20000R}{20000} .$

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Multiplying by 100 to convert it in percentage, we get

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4 0

3 years ago

A gambler has a coin which is either fair (equal probability heads or tails) or is biased with a probability of heads equal to 0

yawa3891 [41]

Answer:

(a) 0.1719

(b) 0.3504

Step-by-step explanation:

For every coin the number of heads follows a Binomial distribution and the probability that x of the 10 times are heads is equal to:

$P(x)=\frac{n!}{x!(n-x)!}*p^x*(1-p)^{10-x}$

Where n is 10 and p is the probability to get head. it means that p is equal to 0.5 for the fair coin and 0.3 for the biased coin

So, for the fair coin, the probability that the number of heads is less than 4 is:

$P(x$

Where, for example, P(0) and P(1) are calculated as:

$P(0)=\frac{10!}{0!(10-0)!}*0.5^0*(1-0.5)^{10-0}=0.0009\\P(1)=\frac{10!}{1!(10-1)!}*0.5^1*(1-0.5)^{10-1}=0.0098$

Then, $P(x$ , so there is a probability of 0.1719 that you conclude that the coin is biased given that the coin is fair.

At the same way, for the biased coin, the probability that the number of heads is at least 4 is:

$P(x\geq4 )=P(4)+P(5)+P(6)+...+P(10)$

Where, for example, P(4) is calculated as:

$P(4)=\frac{10!}{4!(10-4)!}*0.3^4*(1-0.3)^{10-4}=0.2001$

Then, $P(x\geq4 )=0.3504$ , so there is a probability of 0.3504 that you conclude that the coin is fair given that the coin is biased.

7 0

3 years ago