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IgorLugansk [536]
3 years ago
11

The trinomial x2 – 3x – 4 is represented by the model.

Mathematics
2 answers:
Hunter-Best [27]3 years ago
6 0

Answer:

Option A - (x + 1) and (x – 4)

Step-by-step explanation:

Given : The trinomial x^2-3x-4 is represented by the model.

To find : What are the factors of the trinomial?

Solution : The given trinomial is a quadratic equation y=ax^2+bx+c

so we solve using by discriminant method.

Solution of x is x=\frac{-b\pm\sqrt{b^2-4ac}}{2a}

Comparing with given quadratic equation y=x^2-3x-4

where a=1, b=-3, c=-4  

Solution is given by

x=\frac{-(-3)\pm\sqrt{(-3)^2-4(1)(-4)}}{2(1)}

x=\frac{3\pm\sqrt{9+16}}{2}

x=\frac{3\pm\sqrt{25}}{2}

x=\frac{3\pm5}{2}

x=\frac{3+5}{2},\frac{3-5}{2}

x=4,-1

The factors are (x-4),(x+1)

Therefore, Option A is correct.

The factors of trinomial x^2-3x-4=(x-4)(x+1)

podryga [215]3 years ago
3 0
For ax^2+bx+c
if a=1 then we can factor it into (x+r)(x+t) where rt=c and r+t=b

given
1x^2-3x-4
what 2 numbers multiply to get -4 and add to get -3?
-4 and 1

(x+1)(x-4)
answer is the first option
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6 0
3 years ago
Read 2 more answers
What’s this problem
Bezzdna [24]

Answer:

use FOIL- Firsts Outsides Insides Lasts

  1. Multiply the -4 and -3 as they are the first numbers of each brackets -4x-3=12
  2. Next the outsides so -4x6i as they are on the outskirts of each brackets -4x6i= -24i
  3. Insides so 3i and -3 as they are in the centre of the two brackets 3ix-3= -9i
  4. Lasts so 3i and 6i as they are at the end of each bracket 3ix6i=18i^2 ( i squared)
  5. add the answers together - 12+-24i+-9i+18i^2= 12-24i-9i+18i^2
  6. Simplify by adding like terms which is -24i and -9i.
<h3>12+-33i+18i^2 is the answer </h3>

3 0
4 years ago
<img src="https://tex.z-dn.net/?f=9%20%5Cfrac%7B9%7D%7B10%7D%20%20%2B%202%20%5Cfrac%7B1%7D%7B4%7D%20%20%3D%20%20%5C%5C%20%206%20
frez [133]

Answer:

1. 445\frac{1}{2}

2. -1\frac{1}{12}

3. 2\frac{11}{30}

Step-by-step explanation:

1. 9\frac{9}{10} +2\frac{1}{4}

I like to make it an improper fraction first.

\frac{99}{10}+\frac{9}{4}

Now take the LCM. The LCM is 20.

\frac{198}{20} +\frac{45}{20}

Now add them.

\frac{8910}{20}

Make this into a mixed number.

445\frac{1}{2}

That's your answer for number 1.

2. 6\frac{1}{4} -7\frac{1}{3}

Do the same thing as the previous addition problem but subtract instead.

\frac{25}{4} -\frac{22}{3}

\frac{75}{12} -\frac{88}{12}

-\frac{13}{12}=-1\frac{1}{12}

-1\frac{1}{12} is your answer for number 2.

3. 8\frac{2}{3}-6\frac{3}{10}

\frac{26}{3} -\frac{63}{10}

\frac{260}{30}-\frac{189}{30}

\frac{71}{30}=2\frac{11}{30}

2\frac{11}{30} is your answer for number 3.

I hope this helps! Let me know if you need help or if I got anything wrong :)

5 0
3 years ago
Ellie has a delivery van which she is going to deliver boxes each box is a cuboid brain.ly 45cm by 40cm by 35cm the space in the
jek_recluse [69]

Answer:

It will take Ellie 64 minutes to put as many boxes as possible.

Step-by-step explanation:

Let us work with meters.

The dimensions of Ellie's boxes in meters are: 0.45m by 0.40m by 0.35 ( <em>to convert from centimeters to meters we just divide by 100, because 1m =100cm).</em> therefore the volume of each box is:

<em>V_{box}=0.45m*0.40m*0.35m=0.063m^3</em>

Now the dimensions of the empty van are 3.6m by 1.6m by 2.1 m, therefore its volume V_{van} is:

V_{van}=3.6m*1.6m*2.1m=12.096m^3.

So the amount of boxes that Ellie can put in the van is equal to the volume of the van V_{van} divided by the volume V_{box} of each box:

\frac{V_{van}}{V_{box}} =\frac{12.096}{0.063}=\boxed{192\:boxes }

So 192 boxes can be put into the van.

Now Ellie can put 3 boxes in the van in 1 minute, therefore the amount of time it will take her to put 192 boxes into the van will be:

\frac{192boxes}{3boxes/minute} =\boxed{64\:minutes}

So it takes Ellie 64 minutes to put as many boxes into the van as she can.

4 0
3 years ago
A student takes a multiple-choice test that has 11 questions. Each question has five choices. The student guesses randomly at ea
marissa [1.9K]

Answer:

a) P(6) = 0.0097

b) P(More than 3) = 0.1611

Step-by-step explanation:

For each question, there are only two possible outcomes. Either it is guessed correctly, or it is not. Questions are independent of each other. So we use the binomial probability distribution to solve this question.

Binomial probability distribution

The binomial probability is the probability of exactly x successes on n repeated trials, and X can only have two outcomes.

P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}

In which C_{n,x} is the number of different combinations of x objects from a set of n elements, given by the following formula.

C_{n,x} = \frac{n!}{x!(n-x)!}

And p is the probability of X happening.

A student takes a multiple-choice test that has 11 questions.

This means that n = 11

Each question has five choices.

This means that p = \frac{1}{5} = 0.2

(a) Find P (6)

This is P(X = 6).

P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}

P(X = 6) = C_{11,6}.(0.2)^{6}.(0.8)^{5} = 0.0097

P(6) = 0.0097

(b) Find P (More than 3).

Either P is 3 or less, or it is more than three. The sum of the probabilities of these outcomes is 1. So

P(X \leq 3) + P(X > 3) = 1

We want P(X > 3). So

P(X > 3) = 1 - P(X \leq 3)

In which

P(X \leq 3) = P(X = 0) + P(X = 1) + P(X = 2) + P(X = 3)

P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}

P(X = 0) = C_{11,0}.(0.2)^{0}.(0.8)^{11} = 0.0859

P(X = 1) = C_{11,1}.(0.2)^{1}.(0.8)^{10} = 0.2362

P(X = 2) = C_{11,2}.(0.2)^{2}.(0.8)^{9} = 0.2953

P(X = 3) = C_{11,3}.(0.2)^{3}.(0.8)^{8} = 0.2215

P(X \leq 3) = P(X = 0) + P(X = 1) + P(X = 2) + P(X = 3) = 0.0859 + 0.2362 + 0.2953 + 0.2215 = 0.8389

Then

P(X > 3) = 1 - P(X \leq 3) = 1 - 0.8389 = 0.1611

P(More than 3) = 0.1611

8 0
4 years ago
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