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d1i1m1o1n [39]
3 years ago
10

Does funko pop do custom orders?

Mathematics
1 answer:
Agata [3.3K]3 years ago
6 0
Yes they do on their website!!
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Subtract the difference of a and 2 from 7
Luden [163]

Answer:

7-(a-2)

Step-by-step explanation:

4 0
3 years ago
Express the following fractions as the sum or difference of two fractions (x^2+y^2)/x^4
zlopas [31]

Answer:

 \frac{1}{x^2} + \frac{y^2}{x^4}

Step-by-step explanation:

\frac{x^2 + y^2}{x^4} = \frac{x^2}{x^4} + \frac{y^2}{x^4} = \frac{1}{x^2} + \frac{y^2}{x^4}

4 0
3 years ago
at the district competition for the 5th grade jump-rope of the year, The following number of jumps without stopping recorded per
Serggg [28]
Well first to find the mean you will have to add up all the numbers together.
5,299 is the total. After you have done that count how many numbers there are. There are 24 numbers. Divide 5,299 by 24 and you get about 220.8. So the mean is 220.8 To find the median number of jumps, write out all the numbers in order from least to greatest. I think you can do this part! The middle number is your answer. If there is no middle number, get the two numbers that are on each side of the middle and divide by 2. Hope I helped!
4 0
3 years ago
Read 2 more answers
the initial vertical velocity of a rocket shot straight up is 42 meters per second. How long does it take for the rocket to retu
Snowcat [4.5K]
It takes 4.3 seconds for the rocket to return to earth.

The equation is:
0=-9.8t^2+v_0t+h_0
where -9.8m/sec² is the acceleration due to gravity, v₀ is the initial velocity, and h₀ is the initial height.  We will go from the assumption that the rocket is launched from the ground, so h₀=0, and we are told that the initial velocity, v₀, is 42.  This gives us:

0=-9.8t^2+42t

We will use the quadratic formula to solve this.  The quadratic formula is:
x=\frac{-b\pm \sqrt{b^2-4ac}}{2a}

Plugging in our information we have:
t=\frac{-42\pm \sqrt{42^2-4(-9.8)(0)}}{2(-9.8)}
\\
\\=\frac{-42\pm \sqrt{1764-0}}{-19.6}
\\
\\=\frac{-42\pm \sqrt{1764}}{-19.6}
\\
\\=\frac{-42\pm 42}{-19.6}=\frac{-42-42}{-19.6} \text{ or } \frac{-42+42}{-19.6}
\\
\\=\frac{-84}{-19.6}\text{ or }\frac{0}{-19.6}
\\
\\=4.3\text{ or }0

x=0 is when the rocket is launched; x=4.3 is when the rocket lands.
8 0
3 years ago
Apparently I'm supposed to do one at a time so here we go again
Nat2105 [25]
A) 60mph
B) 209.7 miles
C) 2 hours and 45 minutes
3 0
3 years ago
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