All categories

3 years ago

The table below shows all of the possible outcomes for rolling two six-sided number cubes.

Mathematics

2 answers:

Vsevolod [243]3 years ago

8 0

Answer: 1/4

Step-by-step explanation: just took the test

frosja888 [35]3 years ago

7 0

Answer:

5/36

Step-by-step explanation:

There are 5 ways that a sum of 8 can be rolled:

6,2 5,3 4,4 3,5 2,5

So, 5 of the 36 possibilities will give you that sum. The probability of rolling that sum is 5/36.

You might be interested in

Solve the equation 4*e+2=1 (mod5)

otez555 [7]

Here's a way to do it.

Let 4e +2 = 5n +1 . . . . . . for some integer n

Then e = (5n -1)/4 = n + (n -1)/4

We want (n-1)/4 to be an integer, so let it be integer m.

... m = (n -1)/4

... 4m = n -1

... 4m +1 = n

Substituting this into our expression for e gives

... e = (5(4m+1) -1)/4 = (20m +4)/4 = 5m +1

e = 5m+1 for any integer m

4 0

3 years ago

12x-4+17x+8 i do not know how to do this

victus00 [196]

Answer:

29x+8 is the answer

Step-by-step explanation:

12x-4+17x+8

=12x+17x-4+8

=29x+8

Hope it will help ^_^

7 0

2 years ago

Can someone help me plz

VikaD [51]

Name all the angles that have v as a vertex

4 0

3 years ago

the line y=2x-4 is dilated bt a scale factor of 3/2 and centered at the origin. Write an equation that represent that image of t

Veseljchak [2.6K]

Answer: $y = 2x -6$

Step-by-step explanation:

Since, If (x,y) represents the coordinates of a line, then after dilation about the origin by the scale factor k, the coordinates of the resultant line will get by the rule,

$(x,y)\rightarrow (kx,ky)$

Here, The equation of the given line is,

y = 2x - 4

x-intercept and y-intercept of the line are (2,0) and (0,-4) respectively,

Hence, the line y = 2x - 4 will be passes through the points (2,0) and (0,-4),

By the above property,

The dilated line about the origin will be passes through the points (3,0) and (0,-6), ( Because (3/2× 2, 3/2×0) = (3,0) and (3/2×0, 3/2×-4) = (0,-6) )

Hence, the equation of transformed line after dilation,

$y-0 = \frac{-6-0}{0-3}(x-3)$