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s2008m [1.1K]
4 years ago
7

The length of a rectangle is four times the width. The perimeter of the rectangle is 45 inches. Write a system of equations that

represents this problem. What is the area of the rectangle?
Mathematics
2 answers:
wolverine [178]4 years ago
8 0

Answer:

Let l be the length and w the width of the rectangle.

P as the perimeter and A as the area.

length of a rectangle is four times the width:

w = w

l = 4w

System of equation : 2l + 2w = P

Substitute:

2(4w) + 2w = 45

8w + 2w

10w = 45

w = 45 / 10

w = 4.5

Solve for l:

l = 4w

l = 4(4.5)

l = 18

Area:

A = lw

A = 18(4.5)

A = 81 in²

marissa [1.9K]4 years ago
6 0

Answer:

area =81  square inches

Step-by-step explanation:

width =w

lenght= 4w

2w + 2(4w)=45

10w=45

w=4.5

l= 4.5(4) = 18

4.5+4.5 +18+18 = 45

Area = l*w

4.5*18 = 81

Area= 81 square inches

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This means, for instance, to see if it can be simplified at all.

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So, all-in-all, the left hand side of your inequality can be written as: 5x+2

Now, let's work on the right hand side of your inequality, the 32

The right hand side of your inequality can be written as: 32

So with these (any) simplifications, the inequality we'll set out to solve is:

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