The length of a rectangle is four times the width. The perimeter of the rectangle is 45 inches. Write a system of equations that represents this problem. What is the area of the rectangle?
2 answers:
Answer:
Let l be the length and w the width of the rectangle.
P as the perimeter and A as the area.
length of a rectangle is four times the width:
w = w
l = 4w
System of equation : 2l + 2w = P
Substitute:
2(4w) + 2w = 45
8w + 2w
10w = 45
w = 45 / 10
w = 4.5
Solve for l:
l = 4w
l = 4(4.5)
l = 18
Area:
A = lw
A = 18(4.5)
A = 81 in²
Answer:
area =81 square inches
Step-by-step explanation:
width =w
lenght= 4w
2w + 2(4w)=45
10w=45
w=4.5
l= 4.5(4) = 18
4.5+4.5 +18+18 = 45
Area = l*w
4.5*18 = 81
Area= 81 square inches
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