Answer:
-83, -82, and -81
Step-by-step explanation:
Step 1: Declare your variable
Let x represent the largest of the 3 consecutive integer
Integer 1: x
Integer 2: x + 1
Integer 3: x + 2
Step 2: Create an equation
(x) + (x + 1) + (x + 2) = -246
Step 3: Solve
x + x + 1 + x + 2 = -246
3x + 3 = -246
3x = -249
x = -83
FInd the other 2 numbers
Integer 1: -83
Integer 2: -82
Integer 3: -81
Step 4: Therefore Statement
Therefore the 3 consecutive numbers are -83, -82, and -81
32^3/5 = 8
64^2/3 = 16
81^1/4 = 3
49^1/2 = 7
125^2/3 = 25
now just put them in order from the smallest value to the largest
Answer:
Will you give me the numbers so I can give you the answer?
Step-by-step explanation:
Answer:
a = 4, p = 2, q = - 1
Step-by-step explanation:
Expand the right side of the identity, then compare the coefficients of like terms with those on the left side.
a(x - p)² + q ← expand (x - p)² using FOIL
= a(x² - 2px + p²) + q ← distribute parenthesis
= ax² - 2apx + ap² + q
Compare coefficients of x² term
a = 4
Compare coefficients of x- term
- 2ap = - 16, that is
- 2(4)p = - 16
- 8p = - 16 ( divide both sides by - 8 )
p = 2
Compare constant terms
ap² + q = 15 , that is
4(2)² + q = 15
16 + q = 15 ( subtract 16 from both sides )
q = - 1
Thus a = 4, p = 2, q = - 1
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