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3 years ago

Please Help Me.... I need Help Help Badly If i dont Get my Grade Up ima Be Sent to Boot Camp

Mathematics

1 answer:

timama [110]3 years ago

7 0

Mark that person as brainlist

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Please help i need help

lora16 [44]

Answer:

yes you hrlp me thank you so much

7 0

3 years ago

Use substitution method <br>3x +4y+175x-2y=11

Viefleur [7K]

$3x +4y+175x-2y=11$

$4y-2y+175x+3x=11$

$2y+178x=11$

$2y=11-178x$

$y=\frac{11-178x}{2}$

$y=-89x+\frac{11}{2}$

$178x=-2y+11$

$x=\frac{-2y+11}{178}$

$x=\frac{-1}{89} y+\frac{11}{178}$

4 0

2 years ago

Heyy yall im sorry I keep asking but dang math hard haha well please help if you can. if you can't no worries

artcher [175]

Answer: TSR, RST, S

Step-by-step explanation:

7 0

2 years ago

Evaluate the expression when c=4, d=6, and e=10 20-C

Svetach [21]

You just subtract 4 from 20
20-4 which is 16

6 0

3 years ago

50 random teenagers were asked how many hours a day they use their phone. They spent an average of 7 hours a day with a standard

tatyana61 [14]

Answer:

The margin of error for the true mean number of hours a teenager spends on their phone is of 0.4 hours a day.

Step-by-step explanation:

We have the standard deviation of the saple, so we use the t-distribution to solve this question.

The first step to solve this problem is finding how many degrees of freedom, we have. This is the sample size subtracted by 1. So

df = 50 - 1 = 49

95% confidence interval

Now, we have to find a value of T, which is found looking at the t table, with 49 degrees of freedom(y-axis) and a confidence level of $1 - \frac{1 - 0.95}{2} = 0.975$ . So we have T = 2

The margin of error is:

$M = T\frac{s}{\sqrt{n}} = 2\frac{1.3}{\sqrt{50}} = 0.4$

In which s is the standard deviation of the sample and n is the size of the sample.

The margin of error for the true mean number of hours a teenager spends on their phone is of 0.4 hours a day.

4 0

2 years ago