Question

In the figure to the right, OC=10, m

Answer 1

Answer:

Let AB be the flagstaff and CD be the vertical tower.

AB=10m=EC

BC=20m=AE

In triangle ABC we have,

tanx=AB/BC

tanx=10/20

1/tanx=20/10

10/tanx=20...........1

In triangle ADE we have

tan(90-x)=DE/AE

cotx=DE/20

1/cotx=20/DE

DE/cotx=20..............2

by eq1 and. eq 2 we get

10/tanx=DE/cotx

10/(AB/BC)=DE/(BC/AB)

10/(10/20)=DE/(20/10)

10×20/10=DE×10/20

DE=40m

Therefore height of vertical tower = DE+EC=40+10=50m