Answer:
20
15
11
Step-by-step explanation:
Answers off Edgenuity
Answer:
1.92 or 4.56 answer when rounded to 100th
The conclusion is that since the value of 0.028 is less than 0.05 so we reject the null hypothesis at 5% level of significance and conclude that the mean of the difference in SAT writing scores for all students who take SAT prep class is equal to 0.
<h3>What is a null hypothesis?</h3>
A null hypothesis is a hypothesis that there is no significant difference between specified populations, any observed difference being due to sampling error.
Here, the effect of a one-day SAT prep class at a 5% level of significance was assessed. Since the value of 0.028 is less than 0.05 so we reject the null hypothesis at 5% level of significance and conclude that the mean of the difference in SAT writing scores for all students who take SAT prep class is equal to 0.
Learn more about hypothesis on:
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10 1/2 + 10 + 7 + 6 + 3 1/2 +4
10+1/2+27+3+1/2
40+1/2+1/2
40+2/2
40+1
41
Answer:
$18
Step-by-step explanation:
we proceed by first solving for the unit cost of a sheet
then calculate the cost for any number of sheet
We are told that a builder could buy 6 sheets for the cost of $9
this means that one sheet would cost 9/6= $1.5
Now the builder buys 12 sheets
therefore the cost of 12 sheets will be
12*1.5= $18
