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3 years ago

26.59 x 2.5 What does this equal..?

Mathematics

2 answers:

Oliga [24]3 years ago

4 0

Answer:

66.475

Step-by-step explanation:

Multiply without the decimals then put the decimal point in the answer.

26.59 has 2 decimal places and 2.5 has 1 decimal place so the answer should have 3 decimal places

vredina [299]3 years ago

3 0

Answer:

66.475

Step-by-step explanation:

You might be interested in

The function h(x) = x2 + 14x + 41 represents a parabola. Part A: Rewrite the function in vertex form by completing the square. S

denpristay [2]

Given the function h(x)=x^2+14x+41, to solve by completing square we procced as follows;
x^2+14x+41=0
x^2+14x=-41
but;
c=(b/2)^2
and b=14
hence;
c=(14/2)^2=49
substituting the value of c in the expression we get:
x^2+14x+49=-41+49
x^2+14x+49=8
(x+7)^2=8
this can be written in vertex form;
h(x)=a(x-h)^2+k
where:
(h,k) is the vertex;
thus
(x+7)^2=8
h(x)=(x+7)^2-8
hence the vertex will be at the point:
(-7,-8)

3 0

3 years ago

Consider the spiral given by c(t) = (e2t cos(2t), e2t sin(2t)). Show that the angle between c and c' is constant. c'(t) = _____L

Tcecarenko [31]

Answer:

angle is 45° which is constant

Step-by-step explanation:

We use formula for two vectors a and b to calculate angle θ between them by formula

cos θ = a . b / magnitude of a  × magnitude of b

Please see the attached file

8 0

2 years ago

The hypotenuse of a right-angled triangle is 61 cm. If one of the remaining two sides is

igomit [66]

Answer:

60cm

Step-by-step explanation:

the length of other side = sqrt (square root) hypotenuse^2 - the length of thrid side^3 = sqrt 61^2 - 11^2 = sqrt 60^2 = 60

8 0

2 years ago

A very large batch of parts (assume a normal distrbution0 from a manufacturer has a mean weight = 43g and a standard deviation =

AVprozaik [17]

Answer:

5.44% probability that exactly 8 of the 16 parts you selected will have weights exceeding 45g

Step-by-step explanation:

To solve this question, we need to understand the normal probability distribution and the central limit theorem.

Normal probability distribution:

Problems of normally distributed samples are solved using the z-score formula.

In a set with mean $\mu$ and standard deviation $\sigma$ , the zscore of a measure X is given by:

$Z = \frac{X - \mu}{\sigma}$

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.

Binomial probability distribution:

The binomial probability is the probability of exactly x successes on n repeated trials, and X can only have two outcomes.

$P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}$

In which $C_{n,x}$ is the number of different combinations of x objects from a set of n elements, given by the following formula.

$C_{n,x} = \frac{n!}{x!(n-x)!}$

And p is the probability of X happening.

Percentage of parts with weights exceeding 45g?

1 subtracted by the pvalue of Z when X = 45. So

We have $\mu = 43, \sigma = 4$

$Z = \frac{X - \mu}{\sigma}$

$Z = \frac{45 - 43}{4}$

$Z = 0.5$

$Z = 0.5$ has a pvalue of 0.6915

1 - 0.6915 = 0.3075

If you slect 16 parts at random form that batch, what is the probability that exactly 8 of the 16 parts you selected will have weights exceeding 45g?

This is P(X = 8) when n = 16, p = 0.3075. So

$P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}$

$P(X = 8) = C_{16,8}.(0.3075)^{8}.(0.6915)^{8} = 0.0544$

5.44% probability that exactly 8 of the 16 parts you selected will have weights exceeding 45g

4 0

3 years ago

What is 388×63+20-45+21

GrogVix [38]

24440 is you answer :)

5 0

2 years ago

Read 2 more answers