What are the first six nonzero multiples of 7??
1 answer:
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Answer:
y = x² - 7
Step-by-step explanation:
The equation of a parabola in vertex form is
y = a(x - h)² + k
where (h, k) are the coordinates of the vertex and a is a multiplier
Here (h, k) = (0, - 7), thus
y = a(x - 0)² - 7
To find a substitute (4, - 3) into the equation
- 3 = a(4 - 0)² - 7, that is
- 3 = 16a - 7 ( add 7 to both sides )
4 = 16a ( divide both sides by 16 )
a = , thus
y = x² - 7