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3 years ago

Which function has zeros -4 and 2

1 answer:

7 0

A function with zeroes at z1 and z2 can be factored into form
f(x)=a(x-z1)(x-z2)
where a is a constant

so
it is
f(x)=a(x-(-4))(x-2) or
f(x)=a(x+4)(x-2)

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11. Find the average rate of change of the equation y = x2 + 4x + 1 on the interval -1 < x < 4.

coldgirl [10]

Answer:

31/5

Step-by-step explanation:

[f(4) - f(-1)] / 4-(-1)

7 0

3 years ago

Please Help!!!! Find two consecutive odd numbers whose product is 47 more than their sum.

fenix001 [56]

7 and 9

7 x 9 = 63

7+9=16

63-16 = 47

7 0

2 years ago

Two communication mask 2km apart and directly north and south of each other. Ubi 's home is 500 m from one and directly east. Ho

pochemuha

Answer: $2061.55\ m$

Step-by-step explanation:

Given

The two communication mask are 2 km apart

Ubi's home is 500 m east of one of the mask

Suppose its distance from the other's is x

From the figure, we can write

$\Rightarrow x^2=2000^2+500^2\\\Rightarrow x^2=4\times 10^6+25\times 10^4\\\Rightarrow x=2061.55\ m\ \text{or}\ 2.061\ km$

7 0

3 years ago

What would be the new value of a after running the program

Nitella [24]

Answer:

Step-by-step explanation:

var a = 3

then a= 3

var b = 5

then b = 5

a ( a new variable ) = a * b = 3 * 5

6 0

3 years ago

Lacy draws a diamond from a standard deck of 52 cards. Without replacing the first card, she then proceeds to draw a second card

Viktor [21]

Answer:

a) i) No

ii) Probability of drawing a diamond and then spade without replacement is 0.0637.

b) i) Yes

ii) Probability of drawing a diamond and then spade with replacement is 0.0625

Step-by-step explanation:

Part a) Without replacement:

i) Are these events independent?

No, because the both events are dependent. because a card taken out of the deck is not replaced back before taking out the other card so the chances of event occur change.

ii) Determine the probability of drawing a diamond and then a spade without replacement.

Probability of drawing a diamond and then spade = (Probability of drawing a diamond) * (Probability of drawing a spade)

Probability of drawing a diamond :

Total cards in deck = 52

Diamonds = 13

Probability of drawing a diamond = 13/52

Probability of drawing a spade:

Total cards in deck after taking diamond = 52 -1 =51

Spades = 13

Probability of drawing a spade = 13/51

Probability of drawing a diamond and then spade = 13/52 * 13/51

= 169/2652

=0.0637

So, Probability of drawing a diamond and then spade without replacement is 0.0637

Part b) With replacements

i) Are these events independent?

Input Yes or No:

Yes, these events are independent because a card taken out of the deck is replaced back before taking out the other card so the chances of event occur doesn't change.

ii) Determine the probability of drawing a diamond and then a spade with replacement.

Probability of drawing a diamond and then spade = (Probability of drawing a diamond) * (Probability of drawing a spade)

Probability of drawing a diamond :

Total cards in deck = 52

Diamonds = 13

Probability of drawing a diamond = 13/52

Probability of drawing a spade:

Total cards in deck after replacing diamond = 52

Spades = 13

Probability of drawing a spade = 13/52

Probability of drawing a diamond and then spade = 13/52 * 13/52

= 169/2704

=0.0625

So, Probability of drawing a diamond and then spade with replacement is 0.0625

7 0

3 years ago