Write the equation of a line that passes through the point (-6,4) and is perpendicular to 7x+2y=10
1 answer:
The slope of 7x+2y=10 is -7/2
and since the line you want is perpendicular to it so its slope is 2/7
its equation is: (y-4) = 2/7(x+6)
y-4 = 2x/7 + 12/7.............(multiply by 7)
7y - 28 = 2x +12
7y - 2x = 40
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