To solve this we assume that the gas is an ideal
gas. Then, we can use the ideal gas equation which is expressed as PV = nRT. At
a constant temperature and number of moles of the gas the product of PV is
equal to some constant. At another set of condition of temperature, the
constant is still the same. Calculations are as follows:
P1V1 =P2V2
V2 = P1 x V1 / P2
<span>V2 = 153 x 4 / 203</span>
V2 = 3 L
Answer:
an exothermic reaction that Increase in entropy
Answer:
VSEPR theory
Explanation:
The valence shell electron pair repulsion theory was propounded by Gillespie and Nylom (1957).
The entire idea of the VSEPR theory is that the shape of a molecule depends on the electrostatic repulsion between electron pairs surrounding the central atom in a molecule which causes these pairs to be separated as far as possible.
The shapes of many molecules can be accurately predicted based on this model.
Answer: Option (4) is the correct answer.
Explanation:
Relation between potential energy and charge is as follows.
U = ![\frac{1}{4 \pi \epsilon_{o}}[\frac{q_{1}q_{2}}{r_{12}} + \frac{q_{2}q_{3}}{r_{23}} + \frac{q_{3}q_{1}}{r_{31}}]](https://tex.z-dn.net/?f=%5Cfrac%7B1%7D%7B4%20%5Cpi%20%5Cepsilon_%7Bo%7D%7D%5B%5Cfrac%7Bq_%7B1%7Dq_%7B2%7D%7D%7Br_%7B12%7D%7D%20%2B%20%5Cfrac%7Bq_%7B2%7Dq_%7B3%7D%7D%7Br_%7B23%7D%7D%20%2B%20%5Cfrac%7Bq_%7B3%7Dq_%7B1%7D%7D%7Br_%7B31%7D%7D%5D)
As it is given that 
, 
, and 
.
Distance between the charges = 1 cm = 
(as 1 cm = 0.01 m)
Hence, putting these given values into the above formula as follows.
U =
= ![9 \times 10^{9} [\frac{1 \times 10^{-8} \times 2 \times 10^{-8}}{10^{-2}} + \frac{2 \times 10^{-8} \times 3 \times 10^{-8}}{10^{-2}} + \frac{3 \times 10^{-8} \times 1 \times 10^{-8}}{10^{-2}}]](https://tex.z-dn.net/?f=9%20%5Ctimes%2010%5E%7B9%7D%20%5B%5Cfrac%7B1%20%5Ctimes%2010%5E%7B-8%7D%20%5Ctimes%202%20%5Ctimes%2010%5E%7B-8%7D%7D%7B10%5E%7B-2%7D%7D%20%2B%20%5Cfrac%7B2%20%5Ctimes%2010%5E%7B-8%7D%20%5Ctimes%203%20%5Ctimes%2010%5E%7B-8%7D%7D%7B10%5E%7B-2%7D%7D%20%2B%20%5Cfrac%7B3%20%5Ctimes%2010%5E%7B-8%7D%20%5Ctimes%201%20%5Ctimes%2010%5E%7B-8%7D%7D%7B10%5E%7B-2%7D%7D%5D)
= ![9 \times 10^{9} [2 + 6 + 1.5]](https://tex.z-dn.net/?f=9%20%5Ctimes%2010%5E%7B9%7D%20%5B2%20%2B%206%20%2B%201.5%5D)
= 
J
= 0.00085 J
Thus, we can conclude that the potential energy of this arrangement, relative to the potential energy for infinite separation, is about 0.00085 J.
