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3 years ago

What four segments are parallel to plane BCHF

1 answer:

6 0

The answere is AD, DG, EG, and AE

If you have a question that says; What four segments are perpendicular to plane ABFE? The answer is segments BC, FH, EG, and AD
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Please help with these questions

AveGali [126]

5 ft.................

8 0

3 years ago

Read 2 more answers

Help please!! i don’t understand this one!

12345 [234]

Answer:

C, D

Step-by-step explanation:

This equation can be solved any of several ways. One that doesn't require much thought is using the quadratic formula.

For ax² +bx +c = 0, the solutions are ...

$x=\dfrac{-b\pm\sqrt{b^2-4ac}}{2a}$

In the given equation, a=2, b=11, c=5, so this becomes ...

$x=\dfrac{-11\pm\sqrt{11^2-4\cdot2\cdot5}}{2\cdot2}=\dfrac{-11\pm\sqrt{81}}{4}\\\\x=\dfrac{-11\pm9}{4}=\left\{-\dfrac{20}{4},-\dfrac{2}{4}\right\}=\{-5,-\frac{1}{2}\}$

The solutions are ...

C. x = -5

D. x = -1/2

_____

My personal favorite is using a graphing calculator. The solutions are the x-intercepts of the expression on the left. That is, where its value is zero, as the equation says.

5 0

3 years ago

a builder could get 6 sheets of sheetrock for $9 if he bought 12 sheets how much money would he have spent

SashulF [63]

He spent $18.
6=$9
12=$18

8 0

3 years ago

Data collected over time on the utilization of a computer core (as a proportion of the total capacity) were found to possess a r

Marianna [84]

Answer:

The probability that the proportion of the core being used at any particular time will be less than 0.10 is 0.08146

Step-by-step explanation:

$\mu =\frac{\alpha }{\alpha +\beta } = \frac{1}{1 + \frac{\beta}{\alpha} }$ 1/3 0.33 = 33.33 %

The Probability of that the proportion of the core being used at any particular time will be less than 0.10 is given by

PDF = $\frac{x^{\alpha -1} (1-x)^{\beta -1} }{\int\limits^1_0 {u^{\alpha -1} (1-u)^{\beta -1}} \, du }$

where x = 0.1

α = 2 and β = 4

PDF = $\frac{0.0729 }{\int\limits^1_0 {u^{\alpha -1} (1-u)^{\beta -1}} \, du }$ = 1.458

CDF = $\frac{\int\limits^{0.1}_0 {t^{\alpha -1} (1-t)^{\beta -1}} \, du }{\int\limits^1_0 {u^{\alpha -1} (1-u)^{\beta -1}} \, du }$ = 0.08146

The probability that the proportion of the core being used at any particular time will be less than 0.10 = 0.08146.

3 0

4 years ago

A book has 200 pages. The number of mistakes on each page is a Poisson random variable with mean 0.01, and is independent of the

aleksandr82 [10.1K]

Answer:

198 pages have no mistakes.

Step-by-step explanation:

We are given the following in the question:

The number of mistakes on a page follows a poison distribution with

$\mu = \lambda = 0.01$

Formula:

$P(X =k) = \displaystyle\frac{\lambda^k e^{-\lambda}}{k!}\\\\ \lambda \text{ is the mean of the distribution}$

We have to find the probability that there are no mistakes on a page.

$P(X =0) = \displaystyle\frac{(0.01)a^0 e^{-0.01}}{0!} = 0.9901$

Thus, approximately 99.01% of the pages have no mistakes.

Number of pages =

$\text{Total number of pages}\times 99.01\%\\\\200\times \dfrac{99.01}{100}\\\\\approx 198$

Thus, 198 pages have no mistakes.

5 0

4 years ago