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Nadusha1986 [10]

3 years ago

9

QUESTION 1 Someone may choose to own a car instead of leasing because: AThe car can be resold later to make some money back. BTh

e car can be resold later for a higher price. CThe maintenance costs for a leased car are generally higher. DThe insurance costs for a leased car are higher.

Computers and Technology

1 answer:

Lorico [155]3 years ago

3 0

This is not a computers and technology question but ill still answer it and the answer to this that i think it is ...A ...but i may be wrong

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How do I translate my Flowchart into Psuedocode?

harkovskaia [24]

Answer:

Step 1

Open the flowchart and locate the startinglocation on the chart.

Step 2

Write the pseudocode that is equivalent to the rectangular process boxes in your diagram.

Step 3

Write the pseudocode for the diamond-shaped decision boxes in your diagram.

Step 4

Write the pseudocode for the end terminator of the flowchart.

Combine all of your converted statements above and you have a flowchart that has been converted to pseudocode.

8 0

3 years ago

Write a recursive method that takes four inputs: a 1-D array of Strings (i.e., exams), the length of this 1-D array (i.e., n), a

ale4655 [162]

Answer:

import java.util.*;

public class Main

{

public static void main(String[] args)

{

String [] exams = {"1;2;3;4;" , "5;6;7;8;" , "9;10;11;12;" };

double[][] n = new double[exams.length][4];

examArray = convert(exams , exams.length , 0 , n);

for(int i = 0 ; i < exams.length ; i++)

{

for(int j = 0 ; j < 4 ; j++)

{

System.out.print(n[i][j] + "\t");

}

System.out.print("\n");

}

}

/* recursive function convert defined here */

public static double[][] convert(String[] exams , int number , int x , double [][] result)

{

if(x==number)

return result;

else

{

String total = exams[x];

String currentScore = "";

int p = 0;

for(int j = 0 ; j<totalScore.length() ; j++)

{

char ch = total.charAt(j);/

if(ch==';')

{

result[x][p] = Double.parseDouble(currentScore);

p++;

currentScore = "";

}

else

{

currentScore = currentScore + Character.toString(ch);

}

}

return convert(exams , number , x+1 , result);

}

}

}

Explanation:

The Java source code defines a recursive function or method called convert that converts the results of three students that sat for four examinations to double or float number and screens their individual results for the four exams on the screen.

5 0

3 years ago

Write an assembly program to find the largest item in an array and store it in a variable named MAXIMUM. Hint: Use both Jump and

Gekata [30.6K]

Use the knowledge of computational language in C++ to write the a code assembly program to find the largest item.

<h3>How to write a maximum function in C++?</h3>

To make it simpler the code is described as:

<em>#include<bitd/stdc++.h></em>

<em>Using namespace std;</em>

<em>Int main(){</em>

<em>Int arr[10]={10, 2, 23, 45, 21, 11};</em>

<em>Int min=INT_MAX;</em>

<em>Int max=INT_MIN;</em>

<em>for(int i=0;i<10;i++)</em>

<em>If(min<arr[i])min=arr[i];</em>

<em>for(int j=0;j<10;j++)</em>

<em>if(max>arr[j])max=arr[j];</em>

<em>Cout<<max<<” “<<min<<endl;</em>

<em>return 0;</em>

See more about C++ code at brainly.com/question/19705654

7 0

2 years ago

(a) How many locations of memory can you address with 12-bit memory address? (b) How many bits are required to address a 2-Mega-

I am Lyosha [343]

Answer:

Follows are the solution to this question:

Explanation:

In point a:

Let,

The address of 1-bit memory to add in 2 location:

$\to \frac{0}{1} =2^1 \ (\frac{m}{m} \ location)$

The address of 2-bit memory to add in 4 location:

$\to \frac{\frac{00}{01}}{\frac{10}{11}} =2^2 \ (\frac{m}{m} \ location)$

similarly,

Complete 'n'-bit memory address' location number is = $2^n.$ Here, 12-bit memory address, i.e. n = 12, hence the numeral. of the addressable locations of the memory:

$= 2^n \\\\ = 2^{12} \\\\ = 4096$

In point b:

$\to Let \ Mega= 10^6$

$=10^3\times 10^3\\\\= 2^{10} \times 2^{10}$

So,

$\to 2 \ Mega =2 \times 2^{20}$

$= 2^1 \times 2^{20}\\\\= 2^{21}$

The memory position for ' $2^n$ ' could be 'n' m bits'

It can use $2^{21}$ bits to address the memory location of 21.

That is to say, the 2-mega-location memory needs '21' bits.

Memory Length = 21 bit Address

In point c:

$i^{th}$ element array addresses are given by:

$\to address [i] = B+w \times (i-LB)$

$_{where}, \\\\B = \text {Base address}\\w= \text{size of the element}\\L B = \text{lower array bound}$

$\to B=\$ 52\\\to w= 4 byte\\ \to L B= 0\\\to address = 10$

$\to address [10] = \$ 52 + 4 \times (10-0)\\$

$= \$ 52 + 40 \ bytes\\$

1 term is 4 bytes in 'MIPS,' that is:

$= \$ 52 + 10 \ words\\\\ = \$ 512$

In point d:

$\to base \ address = \$ t 5$

When MIPS is 1 word which equals to 32 bit :

In Unicode, its value is = 2 byte

In ASCII code its value is = 1 byte

both sizes are < 4 byte

Calculating address:

$\to address [5] = \$ t5 + 4 \times (5-0)\\$

$= \$ t5 + 4 \times 5\\ \\ = \$ t5 + 20 \\\\= \$ t5 + 20 \ bytes \\\\= \$ t5 + 5 \ words \\\\= \$ t 10 \ words \\\\$

3 0

4 years ago

Ebooks are not interactive and only work during the semester the couse is offers.<br> True or false

Iteru [2.4K]

Answer:

<h3><u>FALSE</u></h3>

Explanation:

Interactive eBooks are ebooks that have elements with which your audience can directly interact. This type of content has a lot of touchpoints where the reader can interact, among videos, audios, links, and other interactive content. They have interactive tools for the buyer who is considering your product or service.

5 0

3 years ago