The value of g in the 20 sided regular polygon is 54.
<h3>How to find the angles of a regular polygon?</h3>
If all the polygon sides and interior angles are equal, then they are known as regular polygons.
The polygon given is a 20 sided regular polygon and the measure of each angle is 3g degrees.
Therefore, let's find g.
The sum of interior angles of a 20 sided polygon is as follows:
180(n - 2) = 180(20 - 2) = 180(18) = 3240
Therefore,
each angle = 3240 / 20 = 162
Hence,
162 = 3g
g = 162 / 3
Therefore,
g = 54
learn more on regular polygon here: brainly.com/question/16992545
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Answer: C.) 1.12 seconds
Step-by-step explanation:
Hi, to answer this question we have to substitute h=0 (when the rock hits the ground the height above it is 0) in the equation given:
h (t) = –16t2 + 20
Solving for t (time)
0= –16t2 + 20
16t2=20
t2=20/16
t=√1.25 =1.12 seconds (option C)
Feel free to ask for more if needed or if you did not understand something.
1.x+4y- - 67 =-1
x+4y+67=-1
x+4y=-1-67
X+4y=-68
2.2x-y+2z=-7
2x=-7+y-2z
x=-7/2+1/2y-z
x=-7/2+1/2y-z, y€R, z€R
Warning: I don’t have the € and R
3.-x+2y- -43=5
-x+2y+43=5
-x+2y=5-43
-x+2y=-38
x-2y=38
Hope this helps!
Please mark me brainliest if possible
That is a difference of two square numbers, we can factorize them easily:
<span>0 =-b^2 + 25
b^2 - 25 = 0
(b + 5)(b - 5) = 0</span>
Answer:
Original position: base is 1.5 meters away from the wall and the vertical distance from the top end to the ground let it be y and length of the ladder be L.
Step-by-step explanation:
By pythagorean theorem, L^2=y^2+(1.5)^2=y^2+2.25 Eq1.
Final position: base is 2 meters away, and the vertical distance from top end to the ground is y - 0.25 because it falls down the wall 0.25 meters and length of the ladder is also L.
By pythagorean theorem, L^2=(y -0.25)^2+(2)^2=y^2–0.5y+ 0.0625+4=y^2–0.5y+4.0625 Eq 2.
Equating both Eq 1 and Eq 2: y^2+2.25=y^2–0.5y+4.0625
y^2-y^2+0.5y+2.25–4.0625=0
0.5y- 1.8125=0
0.5y=1.8125
y=1.8125/0.5= 3.625
Using Eq 1: L^2=(3.625)^2+2.25=15.390625, L=(15.390625)^1/2= 3.92 meters length of ladder
Using Eq 2: L^2=(3.625)^2–0.5(3.625)+4.0625
L^2=13.140625–0.90625+4.0615=15.390625
L= (15.390625)^1/2= 3.92 meters length of ladder
<em>hope it helps...</em>
<em>correct me if I'm wrong...</em>
