Answer:
The perimeter of a rhombus with diagonals of 12 feet and 18 feet would be 60 feet.
Step-by-step explanation:
Perimeter of a rhombus: S1 + S2 + S3 + S4 = answer. (S stands for side.)
12 ft. + 18 ft. + 12 ft. + 18 ft. = 60 ft.
Answer:
(C)
Step-by-step explanation:
The diagram is divided ninto 5 parts that is rectangles ABCD, CHGD, GFEH and triangles CIH and DGJ.
Area of rectangle ABCD= 
=
Area rectangle CDHG= 
=
Area rectangle HGFE= 
=
Area of triangles CIH and DIG= 
=
Surface area of the triangular prism=Area of rectangle ABCD+Area rectangle CDHG+Area rectangle HGFE+Area of triangles CIH and DIG
=
Hence, option C is correct.
Vector

.

. So the sum is

.
For the second, the magnitude is the square root of the sum of the squares of the components. This is equal to

.
Isoceleese means then that 2 sides are equal
right triangle so the legs are equal
a^2+b^2=c^2
the legs aer a and b
in isocoleese, a=b
a^2+a^2=c^2
2a^2=c^2
if isocoleese=a then c=?
solve for c
sqrt both sides
a√2=c
if the legs are x feet, then the hyppotonuse is x√2 feet