Let
b-----------> the length side of the square box
h------------> the height of the box
SA---------> surface area of the box
we know that
[volume of the box]=b²*h
volume=256 in³
b²*h=256-------> h=256/b²-----> equation 1
surface area of the box=area of the base+perimeter of base*height
area of the base=b²
perimeter of the base=4*b
surface area=b²+(4*b)*h------> SA=b²+4*b*h-----> equation 2
substitute equation 1 in equation 2
SA=b²+4*b*[256/b²]-----> SA=b²+1024/b-----> SA=(b³+1024)/b
the answer is
the formula of the volume of the box is V=b²*h-----> 256=b²*h
the formula of the surface area of the box are
SA=b²+4*b*h
SA=(b³+1024)/b
Answer:
f(-2) = 21
Step-by-step explanation:
Step 1: Define
f(x) = 3x² - 4x + 1
f(-2) is x = -2
Step 2: Substitute and Evaluate
f(-2) = 3(-2)² - 4(-2) + 1
f(-2) = 3(4) + 8 + 1
f(-2) = 12 + 9
f(-2) = 21
Answer:
Range of F(x) = (-∞ ,72).
Step-by-step explanation:
Range of the function F(x) means the set of values which are taken by the function along its domain.
F(x) = 72 - 
Since coefficient of
is negative on the right side ,
Maximum value of F(x) will come at x = 0.
Which is, F(0) = 72.
Now, as x increases , F(x) decreases , when x will reach infinity ,
F(x) will be reaching negative of infinity .
Thus, F(x) is ranging from -∞ to 72 .
Range of F(x) = (-∞ ,72).
the numbers are 3 and 18
let the first number be n then the second number = 6n and the sum
sum = n + 6n = 21 thus
7n = 21
divide both sides of the equation by 7
n =
= 3
the numbers are 3 and 6 × 3 = 18 → (3 + 18 = 21)
Using the inverse sine of x (32 / 58), the degree is 33.5.