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krok68 [10]
3 years ago
5

What is the gcf of 28 and 60

Mathematics
1 answer:
Vikki [24]3 years ago
3 0

Answer:

4

Step-by-step explanation:

We need to find the factors of each number

28 -

1x28

2x14

4x7

60 -

1x60

2x30

3x20

4x15

5x12

6x10


then we need to find the largest number they have in common

in this case it is 4

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Lixins monthly income consists of a basic salary of $500 and a commission of 4percent on her sales for the month.If her income i
Harman [31]

Answer:

Lixins monthly sales = $18,000

Step-by-step explanation:

Let x be the total sales.

Given:

Basic salary = $500

Commission on sales = 4% = 0.04

Monthly income = $1220

We need to find her sales for the month.

Solution:

First we write the equation for given situation:

Total\ sales = Basic\ Salary + 0.04(Total\ sales)

S = 500 + 0.04x

1200=500+0.04x

0.04x=1220-500

0.04x=720

x = \frac{720}{0.04}

x = \$18,000

Therefore, Lixins monthly sales are $18,000.

8 0
3 years ago
You have a mass of 200g and a volume of 400cc. What is the density
Bess [88]
D=m/v
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4 0
3 years ago
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Expand using the properties and rules for logarithms
malfutka [58]

Consider expression \log_{\frac{1}{2}}\left(\dfrac{3x^2}{2}\right).

1. Use property

\log_a\dfrac{b}{c}=\log_ab-\log_ac.

Then

\log_{\frac{1}{2}}\left(\dfrac{3x^2}{2}\right)=\log_{\frac{1}{2}}3x^2-\log_{\frac{1}{2}}2.

2. Use property

\log_abc=\log_ab+\log_ac.

Then

\log_{\frac{1}{2}}\left(\dfrac{3x^2}{2}\right)=\log_{\frac{1}{2}}3x^2-\log_{\frac{1}{2}}2=\log_{\frac{1}{2}}3+\log_{\frac{1}{2}}x^2-\log_{\frac{1}{2}}2.

3. Use property

\log_ab^k=k\log_ab.

Then

\log_{\frac{1}{2}}\left(\dfrac{3x^2}{2}\right)=\log_{\frac{1}{2}}3+\log_{\frac{1}{2}}x^2-\log_{\frac{1}{2}}2=\log_{\frac{1}{2}}3+2\log_{\frac{1}{2}}x-\log_{\frac{1}{2}}2.

4. Use property

\log_{a^k}b=\dfrac{1}{k}\log_ab.

Then

\log_{\frac{1}{2}}\left(\dfrac{3x^2}{2}\right)=\log_{\frac{1}{2}}3+2\log_{\frac{1}{2}}x-\log_{\frac{1}{2}}2=\log_{\frac{1}{2}}3+2\log_{\frac{1}{2}}x-\log_{2^{-1}}2=\\ \\=\log_{\frac{1}{2}}3+2\log_{\frac{1}{2}}x+\log_22=\log_{\frac{1}{2}}3+2\log_{\frac{1}{2}}x+1.

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7 0
3 years ago
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exis [7]

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Put another way, 742396 is closer to 742400 than it is to 742300. The zeros in 742400 are not significant.

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When we round 742396 to two significant digits, then we get the answer 740000

This time, we only keep the 7 and the 4 as our two important digits. Everything else becomes a 0 which isn't significant. No rounding happens since the 2 after the 4 isn't larger than five. I.e. the number 742396 is closer to 740000 than it is to 750000

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Rounding 0.07284 to three significant digits gets us to the answer 0.0728

We drop the 4 at the end because the 7,2, and 8 take up the three digits we want to keep. The two zeros are not significant.

---------------------------------------------

Rounding 0.07284 to two significant digits gets us the answer 0.073

We keep the 7 and 2 as our two important digits, but bump that 2 up to a 3 because the next digit over is larger than five.

7 0
2 years ago
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is 3 -7 =10 heeeeeeeeeeeeeeeeeeeeeeeeeeeeeeeeeeeeeeeeeeeeeeeeeeeeeeeeeeeeeeeeeeeeeeeeeeeeeeeeeeeeeeeeeeeeeeeeeeeeeeeeeeeeeeeeeee
sdas [7]

Answer:

-4

Step-by-step explanation:

your counting backward from 3

5 0
3 years ago
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