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3 years ago

5a + c = -8a Solve the equation for the variable a

Mathematics

2 answers:

adelina 88 [10]3 years ago

6 0

$5a+c=-8a \\\\ 5a+8a=-c \\\\ 13a=-c \\\\ \boxed{a=-\frac{c}{13}}$

PilotLPTM [1.2K]3 years ago

6 0

$5a+c=-8a \\ 5a+c-5a=-8a-5a \\ c=-13a \\ \frac{c}{-13} = \frac{-13a}{-13} \\ -\frac{c}{13} =a$

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First off, see how much 8700 as principal, yields at 3% APR
that is $\bf \qquad \textit{Simple Interest Earned}\\\\
I = Prt\qquad 
\begin{cases}
I=\textit{interest earned}\\
P=\textit{original amount deposited}\to& \$8700\\
r=rate\to 3\%\to \frac{3}{100}\to &0.03\\
t=years\to &1
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so

$\bf \qquad \textit{Simple Interest Earned}\\\\
I = Prt\quad 
\begin{cases}
I=\textit{interest earned}\\
P=\textit{original amount deposited}\to& \$8700\\
r=rate\to 3\%\to \frac{3}{100}\to &0.03\\
t=years\to &1
\end{cases}
\\\\\\
\implies \boxed{?}\\\\
-----------------------------\\\\
\textit{how much to invest at 6\%?}
\\\\\\
$

$\bf \qquad \textit{Simple Interest Earned}\\\\
(393-\boxed{?}) = Prt\quad 
\begin{cases}
I=\textit{interest earned}\\
P=\textit{original amount deposited}\to& \$\\
r=rate\to 6\%\to \frac{6}{100}\to &0.06\\
t=years\to &1
\end{cases}
\\\\\\
\textit{solve for "P", to see how much should the Principal be}\\\\
\textit{keep in mind that }P+\boxed{?}=393\leftarrow \textit{both yields added}$

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