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melomori [17]
3 years ago
12

Solve for the variable in 7⁄28 = 25⁄x

Mathematics
2 answers:
juin [17]3 years ago
4 0
Simple,

to figure this out, first, cross multiply,

\frac{7}{28} = \frac{25}{x}

7*x=7x
and
28*25=700

Which leaves you 7x=700

Now, divide...

\frac{7x}{7} = \frac{700}{7}

x=100

Thus, your answer.
Otrada [13]3 years ago
3 0
Well, I would do cross multiplication for this problem
 7       25
----    -----
28       x

You would get this equation,
7x = 700

Then, solve that by using division
7x = 700
---   -------
7        7

700 / 7 = 100

Hope this helps
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5/8 of the 64 musicians in a music contest are guitarists. Some of the guitarists play jazz solos, and the rest play classical s
motikmotik

The first thing we must do for this case is find the number of total guitarists.

We have then:

(\frac{5}{8}) * (64) = 40

We now look for the relationship between the number of guitarists playing jazz alone to the total number of guitarists.

We have then:

\frac{x}{40} = \frac{1}{4}

Where,

x: number of guitarists playing jazz alone

From here, we clear the value of x.

x = (\frac{1}{4}) * (40)\\x = 10

Then, the number of guitarists who play classical solo is:

40 - 10 = 30

Answer:

30 guitarists play classical solos in the contest

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4 years ago
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faust18 [17]

Probability that the student got a 'C' GIVEN they are female = number of females that got a C in the test/number of females

From the information given,

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Probability that the student got a 'C' GIVEN they are female = 12/30

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1 year ago
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What is the percent of increase from 8 to 10?
IceJOKER [234]

Answer:

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Please help me I need help please​
MakcuM [25]

Answer:

p = 4

Step-by-step explanation:

Given equation:

x^2+(p-3)y^2-4x+6y-16=0

<u>Standard equation of a circle:</u>

(x-a)^2+(y-b)^2=r^2

(where (a,b) is the centre of the circle, and r is the radius)

If you expand this equation, you will see that the coefficient of y^2 is always one.

Therefore, p-3=1

\implies p=1+3=4

<u>Additional information</u>

To rewrite the given equation in the standard form:

\implies x^2+y^2-4x+6y-16=0

\implies x^2-4x+y^2+6y=16

\implies (x-2)^2-4+(y+3)^2-9=16

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\implies (x-2)^2+(y+3)^2=29

So this is a circle with centre (2, -3) and radius √29

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