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OLEGan [10]
3 years ago
7

How many kilograms make a tonne​

Mathematics
1 answer:
kipiarov [429]3 years ago
7 0
Generally in the US a ton is approximately 907 kilograms and a metric ton is equivalent to 1,000 kilograms
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Does anyone know this?
Flura [38]
Answer: A

Step by step explaining:
4.25x4.25x4.25=
76.76
Then if you round it would get you to your answer.
4 0
3 years ago
Read 2 more answers
Write an equation of the line in slope intercept form that pass through the two
Ber [7]
\bf \begin{array}{lllll}
&x_1&y_1&x_2&y_2\\
%   (a,b)
&({{ -2}}\quad ,&{{ 15}})\quad 
%   (c,d)
&({{ 9}}\quad ,&{{ -18}})
\end{array}
\\\\\\
% slope  = m
slope = {{ m}}= \cfrac{rise}{run} \implies 
\cfrac{{{ y_2}}-{{ y_1}}}{{{ x_2}}-{{ x_1}}}\implies \cfrac{-18-15}{9-(-2)}\implies \cfrac{-18-15}{9+2}
\\\\\\
\cfrac{-33}{11}\implies -3

\bf \stackrel{\textit{point-slope form}}{y-{{ y_1}}={{ m}}(x-{{ x_1}})}\implies y-15=-3[x-(-2)]
\\\\\\
y-15=-3(x+2)\implies y-15=-3x-6\implies y=-3x+9
8 0
3 years ago
In the triangle below,
Evgen [1.6K]

Answer:

x=8.6

Step-by-step explanation:

x=8.6

5 0
2 years ago
Please Help. I really don’t get this concept, if you could explain it in detail it would be very appreciated
Dafna11 [192]
<h3>Answer: 24/25</h3>

=================================================

Explanation:

Sine is given to be negative, and so is tangent. This only happens in quadrant Q4

Recall that y = sin(theta), so if sin(theta) < 0, then we're below the x axis.

If tan(theta) < 0, then this means cos(theta) > 0

So we have y < 0 and x > 0 which places the angle somewhere in Q4.

--------------------------

Draw a right triangle as shown below in the attached image. We have AC = 25 and BC = 7. Use the pythagorean theorem to find that AB = 24

So this is what your steps may look like

a^2+b^2 = c^2

7^2+b^2 = 25^2

b^2+49 = 625

b^2 = 625-49

b^2 = 576

b = sqrt(576)

b = 24

So because AB = 24, we know that the cosine of the angle is adjacent/hypotenuse = 24/25

---------------------------

As an alternative, you could use the trig identity

sin^2(x) + cos^2(x) = 1

and plug in the given value of sine to solve for cosine. The cosine value result will be positive since we're in Q4.

So,

sin^2(x) + cos^2(x) = 1

(-7/25)^2 + cos^2(x) = 1

(49/625) + cos^2(x) = 1

cos^2(x) = 1 - (49/625)

cos^2(x) = (625/625) - (49/625)

cos^2(x) = (625-49)/625

cos^2(x) = 576/625

cos(x) = sqrt(576/625)

cos(x) = sqrt(576)/sqrt(625)

cos(x) = 24/25

This is effectively a rephrasing of the previous section since the pythagorean trig identity is more or less the pythagorean theorem (just in a trig form)

6 0
3 years ago
<img src="https://tex.z-dn.net/?f=%5Csqrt%5B3%5D%7B686x%5E4%20y%5E7%7D" id="TexFormula1" title="\sqrt[3]{686x^4 y^7}" alt="\sqrt
Sergio [31]
This answer is there in picture

5 0
3 years ago
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