Karen measures the width of a garden plot and records that it is 44.25 meters. It's actual width is 45.5. What is the percent er

Question

aliina [53]

2 years ago

14

Karen measures the width of a garden plot and records that it is 44.25 meters. It's actual width is 45.5. What is the percent er

ror in the measurements, to the nearest tenth of a percent?

Mathematics

1 answer:

larisa [96] · Answer 1 · 2022-08-20T02:54:29+03:00

In this question, <span>Karen measures the garden width result in 44.25 m while it's actual width is 45.5m. Then the amount of error that the Karen did would be: 45.5m-44.25m= 1.25m
The percent error would be:
</span>percent error = amount of error/ actual measurement
percent error = 1.25m/ 45.5m *100%=2.7%