Question

AB is tangent to O. If AO=12 and BC=25 what is AB ? The diagram is not to scale.

Answer 1

The answer is A


AO = 12

BC= 25+ 12= 37
you can get help from Pythagoras theorem
${37}^{2} = {12}^{2} + {x}^{2} \\ - {x}^{2} = {12}^{2} - {37}^{2} \\ - {x}^{2} = 144 - 1369 = - 1225 \\1225 = {x}^{2}$
$x = \sqrt{1225} = 35$


good luck