Cracks in a rock from exposure to pressure are an example of

What technique is illustrated in this diagram microbiology

Eduardwww [97]

The technique that is known to be illustrated is said to be DNA hybridization.

<h3>What is DNA hybridization?</h3>

In the study of genome, DNA hybridization is known to be a kind of a molecular biology method that is often used to know the measures or the degree of genetic similarity that exist between a given pools of DNA sequences.

DNA hybridization is also seen as ability of two given strand of complementary DNA that tends to pair with another strand and it is one that can be used to find out other similar DNA sequences in two other kinds of species or within a given genome of a single species.

Note that in the case above, The technique that is known to be illustrated is said to be DNA hybridization.

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4 0

2 years ago

Alternetive tourism is so called to defferentiate from

snow_lady [41]

Answer:

Mass tourism

Explanation:

Alternetive tourism is so called to defferentiate from mass tourism.

5 0

3 years ago

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The point (−2,4) lies on the curve in the xy-plane given by the equation f(x)g(y)=17−x−y, where f is a differentiable function o

Nikitich [7]

The value of $\frac{dy}{dx}$ is -3. $\blacksquare$

<h2>Procedure - Differentiability</h2><h3 /><h3>Chain rule and derivatives</h3><h3 />

We derive an expression for $\frac{dy}{dx}$ by means of chain rule and differentiation rule for a product of functions:

$\frac{d}{dx}[f(x)\cdot g(y)] = [f'(x)\cdot \frac{dx}{dx}]\cdot g(y) + f(x) \cdot [g'(y)\cdot \frac{dy}{dx} ]$

$\frac{d}{dx}[f(x)\cdot g(y)] = f'(x)\cdot g(y) +f(x)\cdot g'(y)\cdot \frac{dy}{dx}$ (1)

If we know that $f(x) \cdot g(y) = 17-x-y$ , $f(-2) = 3$ ,<em> </em> $f'(-2) = 4$ ,<em> </em> $g(4) = 5$ and $g'(4) = 2$ , then we have the following expression:

$-1-\frac{dy}{dx} = (4)\cdot (5) + (3)\cdot (2) \cdot \frac{dy}{dx}$

$-1-\frac{dy}{dx} = 20 + 6\cdot \frac{dy}{dx}$

$7\cdot \frac{dy}{dx} = -21$

$\frac{dy}{dx} = -3$

The value of $\frac{dy}{dx}$ is -3. $\blacksquare$

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<h3>Remark</h3>

The statement is incomplete and full of mistakes. Complete and corrected form is presented below:

<em>The point (-2, 4) lies on the curve in the xy-plane given by the equation </em> $f(x)\cdot g(y) = 17 - x\cdot y$ <em>, where </em> $f$ <em> is a differentiable function of </em> $x$ <em> and </em> $g$ <em> is a differentiable function of </em> $y$ <em>. Selected values of </em> $f$ <em>, </em> $f'$ <em>, </em> $g$ <em> and </em> $g'$ <em> are given below: </em> $f(-2) = 3$ <em>, </em> $f'(-2) = 4$ <em>, </em> $g(4) = 5$ <em>, </em> $g'(4) = 2$ <em>. </em>