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andrew11
[14]
3 years ago
15
At what points does the graph of f(x)=2x^2-4x-16 intersect the x-axis
Mathematics
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2
answers:
Rzqust
[24]
3 years ago
6
0
At points
(4,0) and (-2,0)
, <span>the graph of f(x)=2x^2-4x-16 intersect the x-axis.
</span>
Hope this helps.
<span />
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yulyashka
[42]
3 years ago
5
0
Y = 2x² - 4x - 16
or
2x² - 4x - 16 = y
A graph intersects x-axis if coordinate y is equal 0, substitute 0 to y
2x² - 4x - 16 = 0
divide both side by 2
x² - 2x - 8 = 0
factorize the algebraic expression
(x - 4)(x + 2) = 0
x = 4 or x = -2
The graph intersects x-axis at (4,0) and (-2,0)
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