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WINSTONCH [101]
3 years ago
14

Which is true of a geometric point? A) one-dimensional B) two-dimensional C) three-dimensional Eliminate D) no dimensions, only

position
Mathematics
2 answers:
Vladimir79 [104]3 years ago
5 0
The correct answer is D) no dimensions, only position 
Shkiper50 [21]3 years ago
3 0
The ans is : One dimensional
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I need help with this NO LINKS REAL ANSWERS!!!!!<br>Will give Brainliest
tiny-mole [99]
There are 0 solutions because the lines are parallel and will never intersect.
5 0
3 years ago
Which of the following statements about 42xy – 49x + 30y – 35 are true? Check all of the boxes that apply. One of the factors is
kipiarov [429]

Answer:

One of the factors is (7x + 5).

One of the factors is (6y – 7).

Step-by-step explanation:

3 0
3 years ago
10y-50=<br> 10y−50=<br> \,\,-20<br> −20
densk [106]

Answer:

Therefore the value of 'y' is,

y=3

Step-by-step explanation:

Given:

10y-50=-20

To Find:

y= ?

Solution:

10y-50=-20    ........Given

Step 1. Adding 50 to both the side we get

10y-50+50=-20+50\\10y=30

Step 2. Dividing by 10 on both the side we get

\dfrac{10y}{10}=\dfrac{30}{10}\\\\y=3

Therefore the value of 'y' is,

y=3

6 0
3 years ago
Starting in the 1970s, medical technology allowed babies with very low birth weight (VLBW, less than 1500 grams, about 3.3 pound
cluponka [151]

Answer:

The test statistic value using the VLBW babies as group 1 is z=-2.76±0.01 and the P-value for the test (±0.0001) is 0.0030.

Step-by-step explanation:

This is a hypothesis test for the difference between proportions.

The claim is that the proportion of persons with normal birth weight that graduates from high school is significantly greater than the proportion of persons with very low birth weight that graduates from high school.

Then, the null and alternative hypothesis are:

H_0: \pi_1-\pi_2=0\\\\H_a:\pi_1-\pi_2> 0

The significance level is 0.05.

The sample 1 (VLBW group), of size n1=244 has a proportion of p1=0.77049.

p_1=X_1/n_1=188/244=0.77049

The sample 2 (control group), of size n2=247 has a proportion of p2=0.79757.

p_2=X_2/n_2=197/247=0.79757

The difference between proportions is (p1-p2)=-0.02708.

p_d=p_1-p_2=0.77049-0.79757=-0.02708

The pooled proportion, needed to calculate the standard error, is:

p=\dfrac{X_1+X_2}{n_1+n_2}=\dfrac{188+197}{244+247}=\dfrac{385}{491}=0.988

The estimated standard error of the difference between means is computed using the formula:

s_{p1-p2}=\sqrt{\dfrac{p(1-p)}{n_1}+\dfrac{p(1-p)}{n_2}}=\sqrt{\dfrac{0.988*0.012}{244}+\dfrac{0.988*0.012}{247}}\\\\\\s_{p1-p2}=\sqrt{0.00005+0.00005}=\sqrt{0.0001}=0.0098

Then, we can calculate the z-statistic as:

z=\dfrac{p_d-(\pi_1-\pi_2)}{s_{p1-p2}}=\dfrac{-0.02708-0}{0.0098}=\dfrac{-0.02708}{0.0098}=-2.76

This test is a left-tailed test, so the P-value for this test is calculated as (using a z-table):

P-value=P(t

As the P-value (0.0030) is smaller than the significance level (0.05), the effect issignificant.

The null hypothesis is rejected.

There is enough evidence to support the claim that the proportion of persons with normal birth weight that graduates from high school is significantly greater than the proportion of persons with very low birth weight that graduates from high school.

3 0
3 years ago
Ashley found 2 boxes of sugar in the kitchen. The green box is 1.26 kg and the red box is 1.026 kg. Which box contains more suga
Anni [7]

Answer:

Answer:

Green box contains more sugar.

Step-by-step explanation:

Consider the provided information.

Ashley found 2 boxes of sugar in the kitchen.

The green box says 1.26 kg and the red box says 1.026 kg.

we need to find which box contains more sugar.

To find this we will first check the digit at ones place.

Both the digit has 1 at the ones place. So now check the digit at tenths place.

1.26 has 2 at tenths place while 1.026 has 0 at tenths place.

As we know 2 is greater than 0, thus the number 1.26 is greater than 1.026.

Hence, green box contains more sugar.

4 0
2 years ago
Read 2 more answers
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