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Vladimir [108]
3 years ago
5

A woman is trapped in a burning building, 60 feet above the ground. To rescue the woman, a fireman places the bottom of a large

ladder 40 feet from the base of the building. How long must the ladder be to reach the trapped woman?

Mathematics
1 answer:
AnnyKZ [126]3 years ago
5 0

Height of building =60 feet (where woman is trapped)

distance of bottom of ladder from base of building = 40 feet

This makes a right angled triangle as shown in figure.

here hypotenuse =length of ladder

base = distance of bottom of ladder from base of building = 40 feet

perpendicular =Height of building =60 feet (where woman is trapped)

So here we can use Pythagoras theorem to find the length of ladder.

Hypotenuse² = base² + perpendicular²

height of ladder = √(60² +(40)² = √3600 +1600 = √5200

height of ladder = 72.1 feet

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A stock priced at $100 has a 70% probability of moving up and a 30% probability of moving down. If it moves up, it increases by
masha68 [24]

Answer:

The probability that after two period we will have the same value of $100 is:

p =0.21+0.21 = 0.42

Step-by-step explanation:

We can analyze this situation by cases.

Stock moves up two times

For this case the final value would be:

$100 *1.02*1.02= $104.04

And the probability associated to this event is 0.7*0.7=0.49

Stock moves down two times

For this case the final value would be:

$100 *(1/1.02)*(1/1.02)= $96.117

And the probability associated to this event is 0.3*0.3=0.09

Stock moves up and then down

For this case the final value would be:

$100 *(1.02)*(1/1.02)= $100

And the probability associated to this event is 0.7*0.3=0.21

Stock moves down and then up

For this case the final value would be:

$100 *(1/1.02)*(1.02)= $100

And the probability associated to this event is 0.3*0.7=0.21

So then the probability that after two period we will have the same value of $100 is :

p =0.21+0.21 = 0.42

7 0
3 years ago
What did they do wrong​
Evgen [1.6K]
Add 4 they were supposed to subtract 4. The subtraction sign is actually represented as a negative 2x. I think..
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Ricks family traveled 5/7 of the distance to his grandmother's house on saturday. They traveled 1/2 of the remaining distance on
11Alexandr11 [23.1K]

Answer:

On Sunday they traveled=1/7 of the total distance

Step-by-step explanation:

Total distance to be traveled=x

On Saturday they covered=(5/7)x

Remaining distance=x-(5/7)x=(2/7)x

Sunday=1/2 of the remaining distance=(1/2)×(2/7)x=(1/7)x

On Sunday they traveled=1/7 of the total distance(x)

8 0
3 years ago
What are the domain and range of the piecewise function below? HELP ASAP
Vesna [10]

The domain is the set of all point where you can evaluate the function.

As you can see, the first piece is defined from -infinity to 2 (included).

The second piece is defined from 2 to 6 (excluded).

The third piece is defined from 6 (excluded) to +infinity.

So, the domain of the function is composed by all the real numbers which are not 6:

(-\infty,6)\cup(6,\infty) = \mathbb{R}\setminus\{6\} = \{x \in \mathbb{R}\ :\ x\neq 6\}

As for the range, it is the set of all values taken by the function. We can see that the first piece spans the y axis from 0 to infinity.

The second piece is constantly equal to 2, so it adds nothing.

The third piece spans the y axis from -2 to -infinity, so the range is

(-\infty,-2)\cup[0,\infty) = \mathbb{R}\setminus [2,0) = \{x \in \mathbb{R}\ :\ x\geq 0\ \lor\ x

3 0
4 years ago
Read 2 more answers
Consider points A(1, 6) and B(8, 8). Find point C on the x-axis so AC +BC is a minimum.
Kay [80]

Answer:

The coordinates of the point C that minimizes AC + BC are (-20, 0) or (4, 0)

Step-by-step explanation:

The given coordinates of the points A and B are A(1, 6) and B(8, 8)

The location of the point C = The x-axis

Therefore;

The coordinates of the point C = (x, 0)

The length of the segment AC = √((1 - x)² + (6 - 0)²) = √((1 - x)² + 6²)

The length of the segment BC = √((8 - x)² + (8 - 0)²) = √((8 - x)² + 8²)

At minimum distance of AC + BC, we have;

d(√((1 - x)² + 6²) +√((8 - x)² + 8²))/dx = 0 = (1 - x) × 2 × (0.5 - 1)× (√((1 - x)² + 6²)^(0.5 - 1) + (8 - x) × 2 × (0.5 - 1)× √((8 - x)² + 8²)^(0.5 - 1)

∴ d(√((1 - x)² + 6²) +√((8 - x)² + 8²))/dx = 0 = -(1 - x)/√((1 - x)² + 6²) - (8 - x)/√((8 - x)² + 8²)

-(1 - x)/√((1 - x)² + 6²) = (8 - x)/√((8 - x)² + 8²)

(8 - x)·√((1 - x)² + 6²) = -(1 - x)·√((8 - x)² + 8²)

Squaring both sides gives;

(8 - x)²·((1 - x)² + 6²) = (1 - x)²·((8 - x)² + 8²)

Expanding, using an online tool, we get;

x⁴ - 18·x³ + 133·x² -720·x + 2368 = x⁴ - 18·x³ + 161·x² - 272·x + 128

Which gives;

(161 - 133)·x² - (272 - 720)·x + 128 - 2368 = 28·x² + 448·x - 2240 = 0

Dividing by 28 gives;

x² + 16·x - 80 = 0

(x + 20)·(x - 4) = 0

Therefore, x = -20 or x = 4

The coordinates of the point C that minimizes AC + BC are (-20, 0) or (4, 0)

4 0
3 years ago
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