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3 years ago

Please help me asap, and show work please.

Mathematics

1 answer:

vampirchik [111]3 years ago

6 0

(a) Since you're seeing this problem, you've already been taught that
(TU)² = (TS)×(TR)

(b) (TU)² = (4 in)×(9 in) = 36 in² . . . . . . substitute the given values in the above
.. (TU) = √(36 in²) = 6 in . . . . . . . . . . . . take the square root

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Can someone plz help me solve this problem I need help plz someone help me!

cestrela7 [59]

Answer: 25 < P < 36

15/4 < w < 26/4

35/4 < L < 46/4

Step-by-step explanation:

Perimeter is BETWEEN 25 and 36

25 < P < 36

Graph: O--------------O

25 36

Perimeter = 2L + 2w ; substitute L = w + 5

25 < 2(w + 5) + 2w < 36

25 < 2w + 10 + 2w < 36

25 < 4w + 10 < 36

15 < 4w < 26

$\dfrac{15}{4}$ < w < $\dfrac{26}{4}$

$3\dfrac{3}{4}$ < w < $6\dfrac{1}{2}$

Graph: O------------------------O

$3\dfrac{3}{4}$ $6\dfrac{1}{2}$

Perimeter = 2L + 2w ; L = w + 5 --> w = L - 5

25 < 2L + 2(L - 5) < 36

25 < 2L + 2L - 10 < 36

25 < 4L - 10 < 36

35 < 4L < 46

$\dfrac{35}{4}$ < L < $\dfrac{46}{4}$

$8\dfrac{3}{4}$ < L < $11\dfrac{1}{2}$

Graph: O------------------------O

$8\dfrac{3}{4}$ $11\dfrac{1}{2}$

Note: Make sure you use OPEN dots when graphing.

5 0

4 years ago

The motion of a ship riding at anchor can be modeled by y=25-4 cos (pi/6)t, where y is the water depth in feet and t is the time

balandron [24]

Answer: 29 feet (deepest) at 6 am

21 feet (shallowest) at Midnight & Noon

Step-by-step explanation:

y = -4 cos (π/6)t +25

Amplitude (A) = 4

-A means it is a reflection over the x-axis (starts at minimum)

Period = 2π/B → Period = 12

Phase shift = C/B → Phase Shift = 0

Midline (D) = 25

Midline (D) ± Amplitude (A) = Max & Min

Max: 25 + 4 = 29

Min: 25 - 4 = 21

Change the coordinates of y = cos (x) as follows:

x-value: Add C then divide by B
y-value: Multiply by A then add D

Note that the equation shows: A = -4, B = π/6, C = 0, D = 25

$\begin{array}{c|ccc|cl}\underline{\quad x\quad}&\underline{\quad y\quad}&&\underline{\quad (x+C)/B\quad}&\underline{\quad Ay+D\quad}\\0&1&&0&21&minimum\\\pi&0&&3&25&midline\\\pi &-1&&6&29&maximum\\3\pi/2&0&&9&25&midline\\2\pi&1&&12&21&minimum\\\end{array}$

5 0

4 years ago

What is the value of a in the equation , when ? 3 15 21 39

kupik [55]

Answer:

the mean =19.5

Step-by-step explanation:

8 0

3 years ago

] Monica Geller, head chef at Allesandro's and is looking to update the commercial equipment in her kitchen and bar that will al

liubo4ka [24]

Answer:

The maximum amount that should be spent on the upgrade is $38,298,000.

Step-by-step explanation:

Let the initial purchase be x.

The ROI = 15% of x = 0.15x

At the end of 4 years, salvage value = 10% of x = 0.1x

Current income per day = $16 × 230 = $3680

Expected income per day = $21 × 245 = $5145

Increase in income per day = $5145 - $3680 = $1465

For 4 years (assuming a year is 365 days),

Increase in income = $1465 × 365 × 4 = $2138900

Maintenance and utility cost for 4 years = 4 × $56000 = $224000

At the end of 4 years,

ROI = $2138900 + salvage value = $2138900 + 0.1x - $224000

0.15x = $1914900 + 0.1x

0.05x = $1914900

x = $38298000

5 0

3 years ago

Read 2 more answers

Plz help I need bt tonight

JulijaS [17]

The answer is 25%.

First: work out the difference between the two numbers you are comparing.

Decrease = Original Number - New Number

35-28=7

Then: divide the decrease by the original number and multiply the answer by 100. % Decrease = Decrease ÷ Original Number × 100

7÷

28=.25

.25*100=25

<h2>Answer is 25%.</h2>

7 0

3 years ago