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Stells [14]
3 years ago
10

3/4 of the weight of a bunch of grapes is equivalent to 3/5 of the weight of a papaya. If the grapes way (X +28) pounds what is

the weight of a papaya in terms of X
Mathematics
1 answer:
Margaret [11]3 years ago
4 0
Let p = weight of papaya and g = weight of grapes.

Then (3/4)g = (3/5)p.  Since the weight of grapes is x + 28, 

(3/4)(x + 28) = (3/5)p.  We must solve for x.  To do this, mult. both sides by (5/3):

(5/3)(3/4)(x+28) = (5/3)(3/5)p

Then p = (15/9)(x+28), or (after reduction), p = (5/3)(x+28).


You might be interested in
If y varies directly as x, and y is 18 when x is 5, which expression can be used to find the value of y when x is 11?
Leokris [45]

Answer: The value of y is 39.6 when x = 11 and the required expression is y(11) = 39.6

Step-by-step explanation:

Since we have given that

y varies directly as x.

If y = 18, when x = 5.

So, we need to find the value of y when x is 11.

According to question, we get that

\dfrac{y}{x}=\dfrac{18}{5}=\dfrac{y}{11}\\\\18\times 11=5y\\\\198=5y\\\\\dfrac{198}{5}=y\\\\y=39.6

Hence, the value of y is 39.6 when x = 11 and the required expression is y(11) = 39.6

5 0
3 years ago
He function y=−16x2+v0x models the height of a golf ball in feet x seconds after a player hits it. In the equation of the functi
Leokris [45]

Answer:

V0 = 48 feet per second is the answer.

Step-by-step explanation:

The given function which represents height of a golf ball in feet after x seconds after a player hits it.

y = -16x² + v0x

here v0 is the initial velocity and we have to calculate initial velocity. The ball returns to the ground 3 seconds after it is hit.

After 3 seconds height of the ball will be 0.

Now from the given function

0 = -16(3)² + v0×3

3v = 16×9

v0 = 16×9/3 = 48 feet per second.

8 0
3 years ago
Read 2 more answers
Which inequality correctly compares Two-fifths, Six-sevenths, Five-eighths, and 1?
Ronch [10]

Answer:

<u>2/5 < 5/8 < 6/7 < 1 </u>

   <u>OR</u>    

<u>1 > 6/7 > 5/8 > 2/5</u>

Step-by-step explanation:

It is required to compare Two-fifths, Six-sevenths, Five-eighths, and 1

Two-fifths = 2/5

Six-sevenths = 6/7

Five-eighths = 5/8

So, the given numbers are: 2/5, 6/7, 5/8, and 1

We need to make the numbers in order from the least to the greatest or from the greatest to the least

The easy method is convert the rational numbers to decimal numbers

So,

2/5 = 0.4

6/7 ≈ 0.857

5/8 = 0.625

1 = 1

So, the numbers form the least to the greatest are:

0.4 , 0.625 , 0.857 , 1

So,

2/5 , 5/8 , 6/7 , 1

The inequality correctly compares the numbers are:

<u>2/5 < 5/8 < 6/7 < 1</u>

Or can be written from the greatest to the least as:

<u>1 > 6/7 > 5/8 > 2/5 </u>

6 0
3 years ago
PLEASE HELP I WILL GIVE BRAINIEST!
marshall27 [118]
The distance is (0, 1.3)
7 0
3 years ago
4x +6y =0
PSYCHO15rus [73]
Here, x - 2y = 14
x = 14 + 2y

Now, substitute this value into first equation, 
4x + 6y = 0
4(14 + 2y) + 6y = 0
56 + 8y + 6y = 0
14y = -56
y = -56/14
y = -4

Substitute it into second equation, 
x = 14 + 2(-4)
x = 14 - 8
x = 6

In short, Your Answer would be: (6, -4)

Hope this helps!
4 0
3 years ago
Read 2 more answers
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