Answer:
a = 5
b = 12
c = 13
Step-by-step explanation:
a^2+b^2=c^2
b-a=7(b=a+7)
c=a+8
Then, substitute
a^2+((a+7)*(a+7))=c^2
a^2+a^2+7a+7a+49=c^2
2a^2+14a+49=c^2
Because c = a+8
2a^2+14a+49=(a+8)(a+8)
2a^2+14a+49=a^2+16a+64
a^2-2a=15
a^2-2a-15=0
(a-5)(a+3)=0
a = 5,-3
a = 5(a side cannot be negative)
Plug in a=5 to the other equations to get
a = 5, b = 12, c = 13
Hope it helps <3
{H,o,n,l,u}
Just take away all the duplicate letters and voila. funny that i did that question yesterday.
The median of the data set is 4. The interquartile range is UQ-LQ 5-3=2. The mean of the first set is 3.5. The mean of the second set is 5.5. Since every score went up by two, the mean went up by two as well.
I hope that helps.
Answer:
Step-by-step explanation:
Craig left his house at noon and drove 50 miles per hour until 3PM. Then he drove the next 5 hours at 70 miles per hour. Calculate the average rate of change for the entire trip.
Factor out cosx: cosx(sinx-2)=0
cosx=0 or sinx-2=0
cosx=0 or sinx=2
the largest value of sinx is 1, sinx will never be 2, so cosx=0, x=π/2 or 3π/2 are the two answers.
