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lord [1]
3 years ago
6

Three potential employees took an aptitude test. Each person took a different version of the test. The scores are reported below

. Nico got a score of 81.6; this version has a mean of 72.6 and a standard deviation of 15. Emilio got a score of 225.3; this version has a mean of 205 and a standard deviation of 29. Alissa got a score of 8.08; this version has a mean of 7.2 and a standard deviation of 0.4. If the company has only one position to fill and prefers to fill it with the applicant who performed best on the aptitude test, which of the applicants should be offered the job?
Mathematics
1 answer:
Margaret [11]3 years ago
8 0

Answer:

ALISSA

Step-by-step explanation:

Given the following scores :

NICO:

Score (x) = 81.6

Mean (m) = 72.6

Standard deviation (sd) = 15

EMILIO:

Score (x) = 225.3

Mean (m) = 205

Standard deviation (sd) = 29

ALISSA:

Score (x) = 8.08

Mean (m) = 7.2

Standard deviation (sd) = 0.4

STANDARDIZING THE DIFFERENT APTITUDE TEST SCORES:

OBTAINING THE ZSCORES :

Zscore = (x - mean) / standard deviation

NICO:

Zscore = (81.6 - 72.6) / 15

Zscore = 0.6

EMILIO:

Zscore = (225.3 - 205) / 29

Zscore = 0.7

ALISSA:

Zscore = (8.08 - 7.2) / 0.4

Zscore = 2.2

From the result of the Zscore, the best fit for the position is ALISSA

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Hey there!

An outlier in a data set is a number that is WAY larger or WAY smaller than the others in the data set, or does not really fit in the specified "range". In the first one, 452 is way greater than everything else, so it would be the outlier.

In the second data set, 5 would be our outlier because it is much smaller than all the other numbers.

In the last data set, the numbers are pretty close together, but we need to find one that isn't inside the small range. 0.201 appears to be the outlier in this case.

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16: 5

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quester [9]
Question a

g(x) times \sqrt{x-5}=\sqrt{x^2-5}
divide both sides by √(x-5)
g(x)=\frac{\sqrt{x^2-5}}{\sqrt{x-5}}
g(x)=\frac{(\sqrt{x-5})(\sqrt{x^2-5})}{x-5}
g(x)=\frac{\sqrt{x^3-5x^2-5x+25}}{x-5}


question b
g(x) \space\ times \space\ 1+\frac{1}{x}=x
divide both sides by 1+1/x
g(x)=\frac{x}{1+\frac{1}{x}}
times by x/x
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question c
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question d
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so maybe we squared the whole thing, ya
wait
ah, ya
basically
|x|=(\sqrt{x})^2=(\sqrt{x})(\sqrt{x})
so f(x)=√x


a. g(x)=\frac{\sqrt{x^3-5x^2-5x+25}}{x-5}
b. g(x)=\frac{x^2}{x+1}
c.f(x)=x^2
d. f(x)=\sqrt{x}
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