I believe it's<span> 8cos(x)⁸ - 16cos(x)⁶ + 10cos(x)⁴ - 2cos(x)².
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Alternately, you can write [</span><span><span>1 / (tan(2x) - cot(2x))] + [cos(8x) / (tan(2x) - cot(2x))].
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Answer:
See the proof below
Step-by-step explanation:
For this case we need to proof the following identity:
We need to begin with the definition of tangent:
So we can replace into our formula and we got:
(1)
We have the following identities useful for this case:
If we apply the identities into our equation (1) we got:
(2)
Now we can divide the numerator and denominato from expression (2) by and we got this:
And simplifying we got:
And this identity is satisfied for all:
3x-11=17-4x add 4x to both sides
7x-11=17 add 11 to both sides
7x=28 divide both sides by 7
x=4
the parallel line is 2x+5y+15=0.
Step-by-step explanation:
ok I hope it will work
soo,
Solution
given,
given parallel line 2x+5y=15
which goes through the point (-10,1)
now,
let 2x+5y=15 be equation no.1
then the line which is parallel to the equation 1st
2 x+5y+k = 0 let it be equation no.2
now the equation no.2 passes through the point (-10,1)
or, 2x+5y+k =0
or, 2*-10+5*1+k= 0
or, -20+5+k= 0
or, -15+k= 0
or, k= 15
putting the value of k in equation no.2 we get,
or, 2x+5y+k=0
or, 2x+5y+15=0
which is a required line.
Answer:
The domain is the set of all the values of x, so it would be -3, -5, -6, -9, 0. The range would be every set of y, so it would be 7, -8, -1, -3. Finally, this relation is indeed a function.
Domain: -3, -5, -6, -9, 0
Range: 7, -8, -1, -3
Is it a function? Yes