They are congruent is the answer
Answer:
The volume of the solid is π/40 cubic units.
Step-by-step explanation:
Please refer to the graph below.
Recall that the area of a semi-circle is given by:
The volume of the solid will be the integral from <em>x</em> = 0 to <em>x</em> = 1 of area A. Since the diameter is given by <em>y</em>, then the radius is <em>y/2</em>. Hence, the volume of the solid is:
Substitute:
Simplify:
Integrate:
![\displaystyle V=\frac{1}{2}\pi \left[\frac{x^5}{20}\Big|_0^1\right]](https://tex.z-dn.net/?f=%5Cdisplaystyle%20V%3D%5Cfrac%7B1%7D%7B2%7D%5Cpi%20%5Cleft%5B%5Cfrac%7Bx%5E5%7D%7B20%7D%5CBig%7C_0%5E1%5Cright%5D)
Evaluate:
The volume of the solid is π/40 cubic units.
Answer:
To find the value of sin 450 degrees using the unit circle, represent 450° in the form (1 × 360°) + 90° [∵ 450°>360°] ∵ sine is a periodic function, sin 450° = sin 90°.
Answer:
Elimination isn't exactly the easiest for this situation. But since the equations are in the same form and not solved for the same variable, I would go with elimination. (If they were solved for the same variable, I would go with substitution.) It would require me to make a manipulation on both equations.
I would multiply first equation by 5 and second equation by -2. The reason I would do this is because the y's would have opposite coefficients and when you add opposites you get 0.
The new set of equations would look like this:
20x+10y=45
-14x-10y=2
But I will slope here since we aren't asked to solve it.
Some texts use the term linear combination instead of elimination. They are the same.
a. The area of the rectangle: 16 units²
b. The area of the triangle on the left: 6 units²
c. Area of the triangle on the right: 10 units²
d. Area of the figure: 32 units²
<h3>What is the Area of a Rectangle and a Triangle?</h3>
- Area of a rectangle = (l)(w)
- Area of a triangle = 1/2bh
a. l = 4 units
w = 4 units
Area of the rectangle = (4)(4) = 16 units²
b. b = 3 units
h = 4 units
Area of the triangle on the left = 1/2(3)(4) = 6 units²
c. b = 5 units
h = 4 units
Area of the triangle on the right = 1/2(5)(4) = 10 units²
d. Area of the figure = 16 + 6 + 10 = 32 units²
Learn more about the area of a rectangle and a triangle on:
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