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san4es73 [151]
4 years ago
14

Convert 0.31 into a fraction.

Mathematics
2 answers:
fenix001 [56]4 years ago
4 0

Answer:

Step-by-step explanation:

Hello friend !!!

0.31 as a fraction is \frac{31}{100}

Hope this helps

plz mark as brainliest!!!!!!!

Lesechka [4]4 years ago
4 0

0.31 as a fraction is 31/100

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Find the solutions to 2x⁴-24x²+40=0 and the x-intercepts of the graph of y=2x⁴-24x²+40.
jekas [21]

Answer:

The solutions and the x-intercepts of the polynomial 2x^4-24x^2+40 are:

x=\sqrt{10},\:x=-\sqrt{10},\:x=\sqrt{2},\:x=-\sqrt{2}

Step-by-step explanation:

Given a function <em>f</em> a solution or a root of <em>f</em> is a value x_{0} at which f(x_0)=0.

An x-intercept is a point on the graph where y is zero.

To find the solutions of the polynomial and the x-intercepts 2x^4-24x^2+40 you need to:

First, we need to factor the polynomial expression

Factor the common term

{\left(2 x^{4} - 24 x^{2} + 40\right)} = {\left(2 \left(x^{4} - 12 x^{2} + 20\right)\right)}

We can treat x^{4} - 12 x^{2} + 20 as a quadratic function with respect to x^2

Let u=x^2. We can rewrite x^{4} - 12 x^{2} + 20 in terms of u as follows:

u^2-12u+20

We need to solve the quadratic equation

u^2-12u+20=0

for this we can use the Quadratic Equation Formula:

For a quadratic equation of the form ax^2+bx+c=0 the solutions are

x_{1,\:2}=\frac{-b\pm \sqrt{b^2-4ac}}{2a}

\mathrm{For\:}\quad a=1,\:b=-12,\:c=20:\quad u_{1,\:2}=\frac{-\left(-12\right)\pm \sqrt{\left(-12\right)^2-4\cdot \:1\cdot \:20}}{2\cdot \:1}

u_1=\frac{-\left(-12\right)+\sqrt{\left(-12\right)^2-4\cdot \:1\cdot \:20}}{2\cdot \:1}\\u_1=10

u_2=\frac{-\left(-12\right)-\sqrt{\left(-12\right)^2-4\cdot \:1\cdot \:20}}{2\cdot \:1}\\u_2=2

the solutions to the quadratic equation are:

u=10,\:u=2

Therefore, u^2-12u+20=(u-10)(u-2)

Recall that u=x^2 so

2 x^{4} - 24 x^{2} + 40=2 \left(x^{2} - 10\right) \left(x^{2} - 2\right)=0

Using the Zero factor Theorem: If ab = 0, then either a = 0 or b = 0, or both a and b are 0.

x^2-10=0 roots are x_1=\sqrt{10}; x_2=-\sqrt{10}

x^{2} - 2=0 roots are x_1=\sqrt{2}; x_2=-\sqrt{2}

The solutions and the x-intercepts are:

x=\sqrt{10},\:x=-\sqrt{10},\:x=\sqrt{2},\:x=-\sqrt{2}

Because all roots are real roots the x-intercepts and the solutions are equal.

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Let f(x) = 4x3 + 3x2 − 20x − 15 and g(x) = 4x + 3. Find f of x over g of x.
serg [7]

Answer:

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Step-by-step explanation:

Let f(x) = 4x3 + 3x2 − 20x − 15 and g(x) = 4x + 3. Find f of x over g of x.

\frac{f(x)}{g(x)} \\\frac{4x^3 + 3x^2 - 20x - 15}{4x+3}

4x^2+15x+15+\frac{35}{x-3}

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Step-by-step explanation:

Treatment 1 consists of 40 people and 23 had improved health take 23 and divide it by 40 and you get 0.575 multiply that by 100 and you get 57% do the same for the second question and you get 0.416 multiply by 100 and you get 41%

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