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stellarik [79]
3 years ago
5

Plz help!!!

Mathematics
2 answers:
Harman [31]3 years ago
7 0

we know that f(1)=2 so f^-1(2)=1

so B is correct!

Sholpan [36]3 years ago
4 0

Answer:  The correct option is

(B) f^{-1}(x)=\dfrac{1}{x-1}.

Step-by-step explanation:  We are given to select the correct expression that is the inverse of the following function :

f(x)=\dfrac{x+1}{x}~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~(i)

Let y denotes f(x). Then,

y=f(x)~~~~~~\Rightarrow x=f^{-1}(y).

Substituting this value in equation (i), we get

f(x)=\dfrac{x+1}{x}\\\\\\\Rightarrow y=\dfrac{f^{-1}(y)+1}{f^{-1}(y)}\\\\\\\Rightarrow yf^{-1}(y)=f^{-1}(y)+1\\\\\Rightarrow yf^{-1}(y)-f^{-1}(y)=1\\\\\Rightarrow (y-1)f^{-1}(y)=1\\\\\Rightarrow f^{-1}(y)=\dfrac{1}{y-1}\\\\\Rightarrow f^{-1}(x)=\dfrac{1}{x-1}.

Thus, the required inverse of the given function is

f^{-1}(x)=\dfrac{1}{x-1}.

Option (B) is CORRECT.

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<h2>30% of 8 cups is 2.4 cups</h2>

Step-by-step explanation:

\bold{METHOD\ 1:}\\\\p\%=\dfrac{p}{100}\\\\30\%=\dfrac{30}{100}=0.3\\\\30\%\ of\ 8\ cups\to0.3\cdot8\ cups=2.4\ cups

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4 0
3 years ago
Pleaseee I needed the answerrr now​
loris [4]

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a=3,b=2,c=5

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5 0
3 years ago
The sum of three numbers in <br> g.p. is 21 and the sum of their squares is 189. find the numbers.
sashaice [31]
Let the three gp be a, ar and ar^2
a + ar + ar^2 = 21 => a(1 + r + r^2) = 21 . . . (1)
a^2 + a^2r^2 + a^2r^4 = 189 => a^2(1 + r^2 + r^4) = 189 . . . (2)
squaring (1) gives
a^2(1 + r + r^2)^2 = 441 . . . (3)
(3) ÷ (2) => (1 + r + r^2)^2 / (1 + r^2 + r^4) = 441/189 = 7/3
3(1 + r + r^2)^2 = 7(1 + r^2 + r^4)
3(r^4 + 2r^3 + 3r^2 + 2r + 1) = 7(1 + r^2 + r^4)
3r^4 + 6r^3 + 9r^2 + 6r + 3 = 7 + 7r^2 + 7r^4
4r^4 - 6r^3 - 2r^2 - 6r + 4 = 0
r = 1/2 or r = 2
From (1), a = 21/(1 + r + r^2)
When r = 2:
a = 21/(1 + 2 + 4) = 21/7 = 3
Therefore, the numbers are 3, 6 and 12.
3 0
3 years ago
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