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Soloha48 [4]
3 years ago
15

Find the area of the rhombus if AE = 20 m and DE = 32 m

Mathematics
1 answer:
Fudgin [204]3 years ago
4 0
We have to calculate the area of the rhombus if AE = 20 m and DE = 32 m.The diagonals DB = 2 * DE and AC = 2 * AE.
DB = 2 * 32 = 64 mAC = 2 * 20 = 40 mArea = d1 * d2 / 2 = DB * AC / 2 = 64 * 40 / 2 = 1,280 m²Answer: The area of the rhombus is B ) 1,280 m².
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The quantity q varies inversely with the square of m and directly with the product of r and x. When q is 2.5, m is 4 and the pro
Usimov [2.4K]

Answer:  Third option is correct.

Step-by-step explanation:

Since we have given that

The quantity q varies inversely with the square of m and directly with the product fo r and x.

According to question,

q=k\frac{rx}{m^2}\\\\\text{ where k denotes constant of variation}

Since q=2.5, m=4, rx=8,

So, we put the value of all of theses in our above relation:

q=k\frac{rx}{m^2}\\\\2.5=k\frac{8}{4^2}\\\\2.5=k\frac{8}{16}\\\\2.5=k\frac{1}{2}\\\\2.5\times 2=k\\\\5=k

Hence, Third option is correct.

7 0
4 years ago
Read 2 more answers
Some number subtracted by -6 is 41. Multiply this number by-3. Then divide
Scrat [10]

Answer:

The final number is 26.25.

Step-by-step explanation:

First, solve the beginning sentence.

"Some number" can be represented by x

x - (-6) = 41    

x + 6 = 41

x = 35

Next, solve the second sentence

35*(-3) = -105

Finally, the last sentence

(-105)/(-4) = 26.25

5 0
3 years ago
Question is 15 points
Blababa [14]

sin(x+y)=sin(x)cos(y)-cos(x)sin(y)

also, remember pythagorean rule, sin^2(x)+cos^2(x)=1

given that sin(Θ)=4/5 and cos(x)=-5/13

find sin(x) and cos(Θ)


sin(x)

cos(x)=-5/13

using pythagorean identity

(sin(x))^2+(-5/13)^2=1

sin(x)=+/- 12/13

in the 2nd quadrant, sin is positve so sin(x)=12/13


cos(Θ)

sin(Θ)=4/5

using pythagrean identity

(4/5)^2+(cos(Θ))^2=1

cos(Θ)=+/-3/5

in 1st quadrant, cos is positive

cos(Θ)=3/5


so sin(Θ+x)=sin(Θ)cos(x)+cos(Θ)sin(x)

sin(Θ+x)=(4/5)(-5/13)+(3/5)(12/13)

sin(Θ+x)=16/65



answer is 1st option

7 0
3 years ago
A population of insects increases at a rate of 1.5% per day. About how long will it take the population to double?
never [62]

The <em><u>correct answer</u></em> is:

46.6 days

Explanation:

The general form for exponential growth is

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We also know we want the total amount, A, to be twice that of the initial amount, p:

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\frac{2p}{p}=\frac{p(1.015)^t}{p}&#10;\\&#10;\\ 2=1.015^t

Using logarithms to solve this,

\log_{1.015}(2)=t&#10;\\&#10;\\46.6=t

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