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2 years ago

Find the area of the rhombus if AE = 20 m and DE = 32 m

1 answer:

4 0

We have to calculate the area of the rhombus if AE = 20 m and DE = 32 m.The diagonals DB = 2 * DE and AC = 2 * AE.
DB = 2 * 32 = 64 mAC = 2 * 20 = 40 mArea = d1 * d2 / 2 = DB * AC / 2 = 64 * 40 / 2 = 1,280 m²Answer: The area of the rhombus is B ) 1,280 m².

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20 pointss please help I appreciate it <333

ivanzaharov [21]

Answer:

DE = 7.07 RS = 11.04 not congruent

Step-by-step explanation:

Formula:

$d=\sqrt{(x2-x1)^2 + (y2-y1)^2}$

D (5,0) E (0,-5)

$d=\sqrt{(0-5)^2 + ( -5 - 0)^2}$

$d=\sqrt{(-5)^2 + (-5)^2}$

$d=\sqrt{25+25}$

$d=\sqrt{50}$

d= 7.07

R (-5,-5) S (6,-6)

$d=\sqrt{(6-(-5))^2 + (-6 - (-5))^2 }$

$d=\sqrt{11^2 + (-1)^2}$

$d=\sqrt{121 + 1}$

$d=\sqrt{122}$

d= 11.04

3 0

2 years ago

How is my graphs line be for this question?

tekilochka [14]

Looking at the table everything is correct if that is what you are asking.

3 0

3 years ago

Simplify: –3(x – 5) – 8(y + 2) + (–3)(6 – 4b) A. –3x –8y – 12b – 15 B. –3x –8y + 12b + 15 C. –3x –8y + 12b + 20 D. –3x –8y + 12b

8090 [49]

Distribute
a(b+c)=ab+ac so
-3(x-5)=-3x+15
-8(y+2)+-8y-16
-3(6-4b)=-18+12b
add them together
-3x+15-8y-16-18+12b
associative property
15-16-18-3x-8y+12b
add
-19-3x-8y+12b is the answer which is D

5 0

3 years ago

Read 2 more answers

Joyce paid $140 for an item at the store that was 20 percent of the original price. What was the original price?

Vesna [10]

Answer:

$175

Step-by-step explanation:

Equation for Price Reduction:

Original Price * Percent Remaining of Original = New Price

Plug in the given values into the equation:

Original Price * 0.8 = $140

Divide both sides by 0.8 to isolate the Original Price:

140/0.8 = 175

3 0

2 years ago

Read 2 more answers

Please answer and explain?

Ronch [10]

Answer:

42ml 40+40+20+58+42=200

8 0

2 years ago