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2 years ago

11

W(x)=x^3 - 5x^2 + 8x - 4 I need the x and y intercepts and the behavior of this equation.

1 answer:

Stells [14]2 years ago

4 0

X intercept is where the line crosses the x axis or where y=0
y intercept is where the line crosses the y axis or where x=0

the equation is 3rd degree and the leading coefient is positive so it goes from bottom left to top right, with 2 changes in direction (up to down or down to up)

x intercepts
W(x)=0=x^3-5x^2+8x-4
um, I graphed it and the x intercepts are at x=1 and x=2

y intercept is where x=0
W(0)=0^3-5(0)+8(0)-4=-4
the y intercept is y=-4

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2 years ago

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Sonbull [250]

Answer:

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Step-by-step explanation:

Given

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Required

Possible values of k

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$ax^2 + bx + c = 0$

Subtract $y = x^2 - 2x$ and $y =kx -4$

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Rewrite as:

$x^2 +x(-2 - k) +4=0$

Compare the above equation to: $ax^2 + bx + c = 0$

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$b^2 - 4ac > 0$

So, we have:

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Expand

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Rewrite as:

$k^2 + 4k - 16 + 4 >0$

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Split:

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$k < 2$ or $k >-6$

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3 years ago

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raketka [301]

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Step-by-step explanation:

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