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polet [3.4K]
3 years ago
11

W(x)=x^3 - 5x^2 + 8x - 4 I need the x and y intercepts and the behavior of this equation.

Mathematics
1 answer:
Stells [14]3 years ago
4 0
X intercept is where the line crosses the x axis or where y=0
y intercept is where the line crosses the y axis or where x=0

the equation is 3rd degree and the leading coefient is positive so it goes from bottom left to top right, with 2 changes in direction (up to down or down to up)

x intercepts
W(x)=0=x^3-5x^2+8x-4
um, I graphed it and the x intercepts are at x=1 and x=2

y intercept is where x=0
W(0)=0^3-5(0)+8(0)-4=-4
the y intercept is y=-4
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Which of the following sets of lengths could not be the side lengths of a triangle?
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To find out if the three side lengths can create a triangle, the three smaller lengths must be greater than the longer length.

\bf~Option~A

\sf~3~meters,5~meters,7~meters

\sf3+5=8>7

So this can create a triangle.

\bf~Option~B

\sf1~yard,1.25~yards,1.5~yards

\sf1+1.25=2.25>1.5

So this can create a triangle.

\bf~Option~C

\sf5~inches,10.5~inches,17~inches

\boxed{\sf5+10.5=15.5

So this cannot create a triangle.

\bf~Option~D

\sf15~millimeters,18~millimeters,30~millimeters

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So this can create a triangle.

Therefore, your answer is Option C.
8 0
3 years ago
In a lilac paint mixture , 40% of the. Mixture is white paint ,20%is blue and the rest red how many cups of red paint are used
fredd [130]

Answer: 40%

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3 years ago
How many of each type of Angle the shape has
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Read 2 more answers
THERE ARE 3 BAGS OF APPLES WEIGHING A TOTAL OF 22 1/2 POUNDS. TWO OF THE BAGS WEIGH 6 3/8 POUNDS AND 3 1/4 POUNDS. HOW MUCH DOES
Mkey [24]
I wasn't going to click on this one, but the all-caps enthralled me and hypnotized me.

first off, let's change all the mixed fractions to "improper" and proceed from there, keep in mind that if we subtract the two bags' weight from the total, what's leftover is the 3rd bag's weight.

\bf \stackrel{mixed}{22\frac{1}{2}}\implies \cfrac{22\cdot 2+1}{2}\implies \stackrel{improper}{\cfrac{45}{2}}
\\\\\\
\stackrel{mixed}{6\frac{3}{8}}\implies \cfrac{6\cdot 8+3}{8}\implies \stackrel{improper}{\cfrac{51}{8}}
\\\\\\
\stackrel{mixed}{3\frac{1}{4}}\implies \cfrac{3\cdot 4+1}{4}\implies \stackrel{improper}{\cfrac{13}{4}}\\\\
-------------------------------\\\\

\bf \stackrel{\textit{sum of the two bags}}{\cfrac{51}{8}+\cfrac{13}{4}}\impliedby \textit{our LCD is 8}\implies \cfrac{(1)51+(2)13}{8}
\\\\\\
\cfrac{51+26}{8}\implies \cfrac{77}{8}\\\\
-------------------------------\\\\
\stackrel{total}{\cfrac{45}{2}}~-~\stackrel{two~bags}{\cfrac{77}{8}}\impliedby \textit{our LCD is again 8}\implies \cfrac{(4)45-(1)77}{8}
\\\\\\
\cfrac{180~~-~~77}{8}\implies \cfrac{103}{8}\implies \stackrel{third~bag}{12\frac{7}{8}}
3 0
4 years ago
Help please!!!!!!!!!!!
adell [148]

Answer:

ok give me a min

Step-by-step explanation:

3 0
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