All categories

3 years ago

1-determine o comprimento e a area de um circulo cujas medidas são:

1 answer:

7 0

The question in English
1 Determine the length and area of a circle whose measures are: a) radius 11cm b) radius 4.2 cm c) diameter 42.3 cm

2 considering that a large traditional pizza is 36 cm in radius and a small traditional pizza has 26 cm.Determine the difference between the area of the two pizzas

3.a worker spends 3 hours to clear a circular terrain of 6 meters radius. If the terrain was 12 meters radius, how much time would the worker spend to clean such terrain ???

4, transform the following arcs into radians a) 27 ° b) 81 ° c) 144 ° d) 225 ° d) 315 °

Part 1)
we know that
length of a circle is equal to the circumference
circumference=2*pi*r
area of the circle=pi*r²

part a ) radius 11 cm
circumference=2*pi*11-----> 69.08 cm
area of the circle=pi*11²----> 379.94 cm²

part b) radius 4.2 cm
circumference=2*pi*4.2-----> 26.38 cm
area of the circle=pi*4.2²----> 55.39 cm²

part c ) diameter 42.3 cm
radius r=42.3/2=21.15 cm
circumference=2*pi*21.15-----> 132.82 cm
area of the circle=pi*21.15²----> 1404.59 cm²

Part 2)

area large traditional pizza
r=36 cm
area=pi*36²----> 4069.44 cm²

area small traditional pizza
r=26 cm
area=pi*26²-----> 2122.64 cm²
difference between the area of the two pizzas =4069.44-2122.64
difference between the area of the two pizzas=1946.80 cm²

Part 3)
Area of the circular terrain of 6 meters radius
area=pi*6²-----> 113.04 m²

Area of the circular terrain of 12 meters radius
area=pi*12²-----> 452.16 m²

if a worker spends 3 hours to clear a circular terrain of--------> 113.04 m²
x hours---------------------------> 452.16 m²
x=452.16*3/113.04-----> x=12 hours

Part 4) transform the following arcs into radians
a) 27°
pi radians------> 180°
x radians-----> 27°
x=27*pi/180-----> x=0.15*pi radians------> 0.47 radians

b) 81°
pi radians------> 180°
x radians-----> 81°
x=81*pi/180-----> x=0.45*pi radians------> 1.41 radians

c) 144°
pi radians------> 180°
x radians-----> 144°
x=144*pi/180-----> x=0.80*pi radians------> 2.51 radians

d) 225°
pi radians------> 180°
x radians-----> 225°
x=225*pi/180-----> x=1.25*pi radians------> 3.93 radians


e) 315°
pi radians------> 180°
x radians-----> 315°
x=315*pi/180-----> x=1.75*pi radians------> 5.50 radians


the answer in Portuguese


Parte 1)

nós sabemos isso
comprimento de um círculo é igual à circunferência
circunferência=2*pi*r
área do círculo=pi*r²

parte a )
raio 11 cm
circunferência=2*pi*11-----> 69.08 cm
área do círculo=pi*11²----> 379.94 cm²

parte b) raio 4.2 cm
circunferência=2*pi*4.2-----> 26.38 cm
área do círculo=pi*4.2²----> 55.39 cm²

parte c )
diâmetro 42.3 cm
raio r=42.3/2=21.15 cm
circunferência=2*pi*21.15-----> 132.82 cm
área do círculo=pi*21.15²----> 1404.59 cm²

Parte 2)


área grande pizza tradicionalr=36 cm
área=pi*36²----> 4069.44 cm²


área pequena pizza tradicional
r=26 cm
área=pi*26²-----> 2122.64 cm²
diferença entre a área das duas pizzas =4069.44-2122.64
diferença entre a área das duas pizzas=1946.80 cm²

Parte 3)

Área do terreno circular de 6 metros de raio
área=pi*6²-----> 113.04 m²


Área do terreno circular de 12 metros de raio
área=pi*12²-----> 452.16 m²

se um trabalhador gastar 3 horas para limpar um terreno -----> 113.04 m²
x hours---------------------------> 452.16 m²
x=452.16*3/113.04-----> x=12 horas

Parte 4) transformar os seguintes arcos em radianos
a) 27°
pi radianos------> 180°
x radianos-----> 27°
x=27*pi/180-----> x=0.15*pi radianos------> 0.47 radianos

b) 81°
pi radianos------> 180°
x radianos-----> 81°
x=81*pi/180-----> x=0.45*pi radianos------> 1.41 radianos

c) 144°
pi radianos------> 180°
x radianos-----> 144°
x=144*pi/180-----> x=0.80*pi radianos------> 2.51 radianos

d) 225°
pi radianos------> 180°
x radianos-----> 225°
x=225*pi/180-----> x=1.25*pi radianos------> 3.93 radianos


e) 315°
pi radianos------> 180°
x radianos-----> 315°
x=315*pi/180-----> x=1.75*pi radianos------> 5.50 radianos

You might be interested in

Is this correct not sure

Digiron [165]

Answer:

which didi you pick , but if you pitted the sixeth one is correct

Step-by-step explanation:

because I hope this helps

4 0

2 years ago

What is the answer to the question

vazorg [7]

The answer would be B. linear pair theorem

8 0

3 years ago

Please please please help and solve this with steps, much help needed thank you :) 20 points for this!

leonid [27]

Answer:

$y=\sqrt{\frac{x^4-6x^2+12x+c_1}{2}},\:y=-\sqrt{\frac{x^4-6x^2+12x+c_1}{2}}$

(Please vote me Brainliest if this helped!)

Step-by-step explanation:

$\frac{dy}{dx}y=x^3+2x-5x+3$

$\mathrm{First\:order\:separable\:Ordinary\:Differential\:Equation}$

$\mathrm{A\:first\:order\:separable\:ODE\:has\:the\:form\:of}\:N\left(y\right)\cdot y'=M\left(x\right)$

1. $\mathrm{Substitute\quad }\frac{dy}{dx}\mathrm{\:with\:}y'\:$

$y'\:y=x^3+2x-5x+3$

2. $\mathrm{Rewrite\:in\:the\:form\:of\:a\:first\:order\:separable\:ODE}$

$yy'\:=x^3-3x+3$

$N\left(y\right)\cdot y'\:=M\left(x\right)$

$N\left(y\right)=y,\:\quad M\left(x\right)=x^3-3x+3$

3. $\mathrm{Solve\:}\:yy'\:=x^3-3x+3:\quad \frac{y^2}{2}=\frac{x^4}{4}-\frac{3x^2}{2}+3x+c_1$

4. $\mathrm{Isolate}\:y:\quad y=\sqrt{\frac{x^4-6x^2+12x+4c_1}{2}},\:y=-\sqrt{\frac{x^4-6x^2+12x+4c_1}{2}}$

5. $\mathrm{Simplify}$

$y=\sqrt{\frac{x^4-6x^2+12x+c_1}{2}},\:y=-\sqrt{\frac{x^4-6x^2+12x+c_1}{2}}$

7 0

3 years ago

Read 2 more answers

What is the answer to this?

rusak2 [61]

Answer:

x= -1, y = -1

Step-by-step explanation:

-16x +24y = -8

16x -8y = -8

16y = -16

y=-1

16x = -16

x = -1

7 0

2 years ago

Read 2 more answers

Consider two competing firms in a declining industry that cannot support both firms profitably. Each firm has three possible cho

yaroslaw [1]

Answer:

a) attached below

b) ( T,T )

c) The Pure-strategy Nash equilibria are : ( N,E ) and ( E,N )

d) The mixed-strategy Nash equilibrium for Firm 1 = ( 1/3 , 0, 2/3 )

while the mixed -strategy Nash equilibrium for Firm 2 = ( 1/3 , 0, 2/3 )

Step-by-step explanation:

A) write down the game in matrix form

let: E = exit at the industry immediately

T = exit at the end of the quarter

N = exit at the end of the next quarter

matrix is attached below

B) weakly dominated strategies is ( T,T )

C) Find the pure-strategy Nash equilibria

The Pure-strategy Nash equilibria are : ( N,E ) and ( E,N )

D ) Find the unique mixed-strategy Nash equilibrium

The mixed-strategy Nash equilibrium for Firm 1 = ( 1/3 , 0, 2/3 )

while the mixed -strategy Nash equilibrium for Firm 2 = ( 1/3 , 0, 2/3 ) since T is weakly dominated then the mixed strategy will be NE

Assume that P is the probability of firm 1 exiting immediately ( E )

and q is the probability of firm 1 staying till next term ( N ) ∴ q = 1 - P.

hence the expected utility of firm 2 choosing E = 0 while the expected utility of choosing N = 4p - 2q .

The expected utilities of E and N to firm 2 =

0 = 4p - 2q = 4p - 2 ( 1-p) = 6p -2 which means : p = 1/3 , q = 2/3

4 0

3 years ago