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2 years ago

How to find mass when given density and volume?

Mathematics

1 answer:

Evgesh-ka [11]2 years ago

5 0

Mass equals density times volume

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Find the value of x.

mixas84 [53]

Answer:

x=3

Step-by-step explanation:

BRAINLIEST plzzzzzzzzzzzzzzzzzz

8 0

2 years ago

Solve the system using elimination. ''x-3y=9 and -x+3y=-9

DiKsa [7]

Answer:

Infinitely many solutions.

Step-by-step explanation:

Let's solve your system by elimination.

x−3y=9;−x+3y=−9

x−3y=9

−x+3y=−9

Add these equations to eliminate x:

0=0

<u>Answer:</u>

Infinitely many solutions.

6 0

2 years ago

The 17th term of an Arithmetic sequence is 51. If the commons difference is 7, what is the first term ?

vovikov84 [41]

Answer:

The first term is:

$a_1=-61$

Step-by-step explanation:

The arithmetic sequence is defined by

$a_n=a_1+\left(n-1\right)d$

where

$a_1$ is the first term

$d$ is the common difference

the 17th term of an arithmetic sequence is 51.

i.e. $a_{17}=51$

$a_n=a_1+\left(n-1\right)d$

$a_{17}=a_1+\left(17-1\right)d$

$51=a_1+\left(17-1\right)7$ ∵ $n = 17$ , $a_{17}=51$ , $d=7$

$a_1+112=51$ ∵ $\left(17-1\right)\cdot \:\:7=112$

$a_1=-61$

Therefore, the first term is:

$a_1=-61$

8 0

2 years ago

Six more than five times a number x is at least twenty one

LUCKY_DIMON [66]

5x3=15. 15+6=21. The answer would be 3

8 0

2 years ago

3 On a coordinate grid, the location of a lighthouse is at L, and the location of a buoy is at B. At noon, a ship is at the midp

Zarrin [17]

Answer:

$(\frac{1}{2}, 2)$

Step-by-step explanation:

Using the midpoint formula, $M(\frac{x_1 + x_2}{2}, \frac{y_1 + y_2}{2})$ , we can find the coordinates that represents the position of the ship at noon.

Let $L(-4, 7) = (x_1, y_1)$ (given on the coordinate plane)

$B(5, -3) = (x_2, y_2)$ (given also)

Plug in the values into the formula and solve as follows:

$M(\frac{-4 + 5}{2}, \frac{7 +(-3)}{2})$

$M(\frac{1}{2}, \frac{7 - 3}{2})$

$M(\frac{1}{2}, \frac{4}{2})$

$M(\frac{1}{2}, 2)$

Position of the ship at noon is best represented at $(\frac{1}{2}, 2)$

5 0

3 years ago