Answer:
Two hundred seventy three thousand and fifty .
Step-by-step explanation:
Given : (27 thousands 3 hundreds 5 ones) x 10
Solution:
27 thousands 3 hundreds 5 ones = 27,305
So, 

Periods are counted from last .
The 1st period consists of ones, tens and hundred.
The 2nd period consists of thousand, 10 thousand and 100 thousands.
The 3rd period consists of million, 10 million and 100 million.
So, 273,050 is Two hundred seventy three thousand and fifty
Hence (27 thousands 3 hundreds 5 ones) x 10 is Two hundred seventy three thousand and fifty .
First, you know that B is the mid point, meaning AB is equal to BC. Therefore, you can set up the equation: x+5=2x-11. Then, you solve for x. Once you are done solving, you should get 16. Hope this helps!
Answer:
cool, how long did it take
Ok, here we go:
5 cars total.
1. Rachel - first car in line, yellow, SUV
2. blue car (Rachel is in front of the blue car), convertible, Anton
3. minivan - third car in line, Diego
4. white car, sedan, Ingrid
5. green car, immediately behind white car, Yuna, pickup
We know that Rachel is first, a blue car is second and the minivan is third. We know that 3, 4 cannot be a convertible since one is a minivan and the other is a sedan. We also know that a yellow car is in front of the convertible.
Based off of that we know that car 5 cannot be a convertible since 4 is white and not yellow. So 1 or 2 is the convertible and SUV. But we know that Rachel is in front of a blue car and the yellow car is in front of a convertible so that makes car #2 the blue convertible and car #1 the yellow SUV.
Fill in what you do know and start to eliminate the outliers. Hope that helps.