Mon wants to make 5 lbs of the sugar syrup. How much water and how much sugar does he need to make 50% syrup?

3/5 of a conductors club went on the last camping trip. If 39 people went on the trip how many are in the club

zhuklara [117]

Okay so we know that 3/5 of the conductors club went on the last camping trip. We also know that 3/5 of the club is equal to 39 people. All we have to do is find the last 2/5 and add it to our 3/5 to get the answer:

To find how much each 1/5 is, divide 39 by 3. This will give us 13. Then we multiply it by 5, because there are five parts. This gives us 65. So the answer is 65

7 0

3 years ago

EEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEE

nata0808 [166]

Answer

diameter=18 cm

radius=18/2=9cm

Area of circle= pi r^2

 = 3.142*(9)^2

 =254.502 cm^2

Area of square= (l)^2

 =(18)^2

 =324 cm^2

Total shaded area= 324-254.502

 =69.498 cm^2

Hope it helps

Good luck on your assignment

7 0

3 years ago

Help, please I'm taking a test on plato

ratelena [41]

Answer:mark me as brainliest plz

Step-by-step explanation:

it's c

5 0

3 years ago

Read 2 more answers

<img src="https://tex.z-dn.net/?f=%24a%2Ba%20r%2Ba%20r%5E%7B2%7D%2B%5Cldots%20%5Cinfty%3D15%24%24a%5E%7B2%7D%2B%28a%20r%29%5E%7B

riadik2000 [5.3K]

Let

$S_n = \displaystyle \sum_{k=0}^n r^k = 1 + r + r^2 + \cdots + r^n$

where we assume |r| < 1. Multiplying on both sides by r gives

$r S_n = \displaystyle \sum_{k=0}^n r^{k+1} = r + r^2 + r^3 + \cdots + r^{n+1}$

and subtracting this from $S_n$ gives

$(1 - r) S_n = 1 - r^{n+1} \implies S_n = \dfrac{1 - r^{n+1}}{1 - r}$

As n → ∞, the exponential term will converge to 0, and the partial sums $S_n$ will converge to

$\displaystyle \lim_{n\to\infty} S_n = \dfrac1{1-r}$

Now, we're given

$a + ar + ar^2 + \cdots = 15 \implies 1 + r + r^2 + \cdots = \dfrac{15}a$

$a^2 + a^2r^2 + a^2r^4 + \cdots = 150 \implies 1 + r^2 + r^4 + \cdots = \dfrac{150}{a^2}$

We must have |r| < 1 since both sums converge, so

$\dfrac{15}a = \dfrac1{1-r}$

$\dfrac{150}{a^2} = \dfrac1{1-r^2}$

Solving for r by substitution, we have

$\dfrac{15}a = \dfrac1{1-r} \implies a = 15(1-r)$

$\dfrac{150}{225(1-r)^2} = \dfrac1{1-r^2}$

Recalling the difference of squares identity, we have

$\dfrac2{3(1-r)^2} = \dfrac1{(1-r)(1+r)}$

We've already confirmed r ≠ 1, so we can simplify this to

$\dfrac2{3(1-r)} = \dfrac1{1+r} \implies \dfrac{1-r}{1+r} = \dfrac23 \implies r = \dfrac15$

It follows that

$\dfrac a{1-r} = \dfrac a{1-\frac15} = 15 \implies a = 12$

and so the sum we want is

$ar^3 + ar^4 + ar^6 + \cdots = 15 - a - ar - ar^2 = \boxed{\dfrac3{25}}$

which doesn't appear to be either of the given answer choices. Are you sure there isn't a typo somewhere?

7 0

2 years ago

LOOK AT PICTURE FOR PROBLEM (probably more than one answer) ‼️

podryga [215]

Answer:

A and C

Step-by-step explanation:

Two angles are Adjacent when they have a common side and a common vertex (corner point) and don't overlap.

So <7 and <9 are adjacent to <8.

[If there's any mistake, please inform me]

7 0

3 years ago