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enyata [817]
3 years ago
8

Find the equation of the line with slope = 6 and passing through (6,43). Write your equation in the form y = m x + b . Please I

need help right now!
Mathematics
1 answer:
jekas [21]3 years ago
6 0

Answer:

6x - y + 7 = 0

Step-by-step explanation:

To find the equation of line passing through a point and slope of same line is given, we use formula,

y - y₁ = m ( x ₋ x₁)

where, (x₁, y₁) = (6, 43)

and m is a slope of line passing through (x₁, y₁) which is equal to 6.

Substituting all values in above formula. We  get,

⇒ y - 43 = 6 ( x ₋ 6)

⇒ y - 43 = 6x - 36

⇒ 6x - y + 7 = 0

which is required equation.

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Simplify x = cos[2 arcsin(3/5)].<br><br> -7/25<br> 7/25<br> 4/5
Marina CMI [18]

Answer:

7/25

Step-by-step explanation:

Let \theta= \arcsin(\frac{3}{5}) so we have x=\cos(2\theta)

As \cos(2\theta)=\cos^2\theta-\sin^2\theta, we'll have \cos[2\arcsin(\frac{3}{5})]=\bigr[\cos(\arcsin(\frac{3}{5}))\bigr]^2-\bigr[(\sin(\arcsin(\frac{3}{5}))\bigr]^2

To determine \cos(\arcsin(\frac{3}{5})), construct a right triangle with an opposite side of 3 and a hypotenuse of 5. This is because since \theta=\arcsin(\frac{3}{5}), then \sin\theta=\frac{3}{5}=\frac{\text{Opposite}}{\text{Hypotenuse}}. If you recognize the Pythagorean Triple 3-4-5, you can figure out that the adjacent side is 4, and thus, \cos\theta=\frac{4}{5}=\frac{\text{Adjacent}}{\text{Hypotenuse}}. This means that \cos(\arcsin(\frac{3}{5}))=\frac{4}{5}.

Hence, \cos[2\arcsin(\frac{3}{5})]=(\frac{4}{5})^2-(\frac{3}{5})^2=\frac{16}{25}-\frac{9}{25}=\frac{7}{25}

5 0
2 years ago
Factor a number, variable, or expression out of the polynomial shown below.
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3 years ago
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Brilliant_brown [7]
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8 0
3 years ago
Read 2 more answers
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earnstyle [38]

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Please read the answer below.

Step-by-step explanation:

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2. Brazil:

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75 * 1.60 = 120 Canadian dollars

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8 0
3 years ago
Factor the expression. -20x + 32
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Factor -20x+32
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8 0
3 years ago
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