Answer:
21 ft by 66 ft
Step-by-step explanation:
From the question,
P = 2(L+W)............... Equation 1
Where P = Perimeter of the playing Field, L = Length of the playing Field, W = width of the playing Field.
If the Length of the Field is 45 ft longer than the width,
L = 45+W............ Equation 2
Substitute Equation 2 into equation 1
P = 2(45+W+W)
P = 90+4W............. Equation 3
Given: P = 174 ft.
Substitute into equation 3
174 = 90+4W
4W = 174-90
4W = 84
W = 84/4
W = 21 ft.
Substituting the value of W into equation 2
L = 45+21
L = 66 ft.
Hence the dimensions of the playing field is 21 ft by 66 ft
Both are equal y. So you can set them equal to each other
9x+13=2x+48
Subtract 2x from both sides
7x+13=48
Subtract 13 from both sides
7x= 35
X=5
563+8=571 burgers to start with
The answer is 5! Like if you have 3 cookies then add two you would have .. 5! (: any other questions you need help with?
