All categories

3 years ago

Ax+b=c for x how do I solve this can someone help explain it to me.

Mathematics

1 answer:

Dmitry [639]3 years ago

5 0

Answer:

x= c - b / A

please look at the step by step explanation to better understand :)

Step-by-step explanation:

subtract b from the left side and right side

so you are left with Ax = c - b

divide what number c - b is by A

and you are left with x= c - b / A

You might be interested in

If /_\CAT ~= /_\LUV then /_\c ~=/_\L. True or False?

yulyashka [42]

Answer:

true

Step-by-step explanation:

5 0

2 years ago

The first term of an arithmetic sequence is 4 and the tenth term is 67.

serg [7]

Answer:

d = 7

Step-by-step explanation:

The nth term of an arithmetic sequence is

$a_{n}$ = a₁ + (n - 1)d

where a₁ is the first term and d the common difference

Give a₁₀ = 67 and a₁ = 4 , then

a₁ + 9d = 67

4 + 9d = 67 ( subtract 4 from both sides )

9d = 63 ( divide both sides by 9 )

d = 7

8 0

3 years ago

Write an equation involving absolute value for the graph if the points are located at 0 and 0.5

balu736 [363]

Answer:

bro im stuck too

Step-by-step explanation:

6 0

3 years ago

Fran brings home $225 per week working 15 hours of which she is able to save $40. Fran wants to have $1,400 saved at the end of

8_murik_8 [283]

Answer:

225+40+1,400=?

Step-by-step explanation:

8 0

3 years ago

Read 2 more answers

1. Carter will install fencing all around the flat area of his

MariettaO [177]

Answer:

Amount of fencing required = 75 yards

Step-by-step explanation:

Distance between the two points $(x_1,y_1)$ and $(x_2,y_2)$ is given by the formula,

d = $\sqrt{(x_2-x_1)^2+(y_2-y_1)^2}$

Distance between A(3, 6) and B(3, -2) = $\sqrt{(3-3)^2+(6+2)^2}$

= 8 yards

Distance between B(3, -2) and C(-7, 4) = $\sqrt{(3+7)^2+(-2-4)^2}$

= $\sqrt{136}$

= 11.66 ≈ 12 yards

Distance between C(-7, 4) and D(-7, -2) = $\sqrt{(-7+7)^2+(4+2)^2}$

= 6 yards

Distance between D(-7, -2) and E(-3, -2) = $\sqrt{(-7+3)^2+(-2+2)^2}$

= 4 yards

Distance between E(-3, -2) and F(-3, -8) = $\sqrt{(-3+3)^2+(-2+8)^2}$

= 6 yards

Distance between F(-3, -8) and G(3, -8) = $\sqrt{(-3-3)^2+(-8+8)^2}$

= 6 yards

Distance between G(3, -8) and H(10, -12) = $\sqrt{(3-10)^2+(-8+12)^2}$

= $\sqrt{49+16}$

= $\sqrt{65}$

= 8.06 ≈ 8 yards

Distance between H(10, -12) and J(10, 6) = $\sqrt{(10-10)^2+(-12-6)^2}$

= 18 yards

Distance between A(3, 6) and J(10, 6) = $\sqrt{(10-3)^2+(6-6)^2}$

= 7 yards

Since length of fence required = perimeter of the flat area

Perimeter of the given area = 8 + 12 + 6 + 4 + 6 + 6 + 8 + 18 + 7

= 75 yards

Therefore, amount of fencing required = 75 yards

8 0

3 years ago