At 13% significance level, there isn't enough evidence to prove the administrators to claim that the mean score for the state's eighth graders on this exam is more than 280.
<h3>How to state hypothesis conclusion?</h3>
We are given;
Sample size; n = 78
population standard deviation σ = 37
Sample Mean; x' = 280
Population mean; μ = 287
The school administrator declares that mean score is more (bigger than) 280. Thus, the hypotheses is stated as;
Null hypothesis; H₀: μ > 280
Alternative hypothesis; Hₐ: μ < 280
This is a one tail test with significance level of α = 0.13
From online tables, the critical value at α = 0.13 is z(c) = -1.13
b) Formula for the test statistic is;
z = (x- μ)/(σ/√n)
z = ((280 - 287) *√78 )/37
z = -1.67
c) From online p-value from z-score calculator, we have;
P[ z > 280 ] = 0.048
d) The value for z = -1.67 is smaller than the critical value mentioned in problem statement z(c) = - 1.13 , the z(s) is in the rejection zone. Therefore we reject H₀
e) We conclude that at 13% significance level, there isn't enough evidence to prove the administrators to claim that the mean score for the state's eighth graders on this exam is more than 280.
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Answer:
12 miles
Step-by-step explanation:
1/2 inch per 2 miles
3 inches away
3 ÷ 1/2 = 6
6 * 2 = 12
Answer:
Use the slope formula and slope-intercept form
y
=
m
x
+
b
to find the equation.
f
(
x
)
=
3
x
−
1
Step-by-step explanation:
Answer:
first, u need to know the formula for compound interest, which is:
where A is the final amount
P- initial amount
r- percent compounded(interest)
and
n- number of years
so
we have
3.8/100 = 0.038
1+0.038 =1.038
1.038^4 = 1.160885573136
475 * 1.160885573136 = 551.4206472396
approximately $551.42
1. Commutative property of adfition
2. Multiplicative inverse
3. Associative property of addition
4. Distributive property
5. Additive identity
